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What is the resistance of an electric appliance with 1.5KW heating tube and 220V voltage?
P=1.5kW=1500W
Because P = UI = u * (U / R) = (u ^ 2) / R
Therefore, its resistance is high
R = (u ^ 2) / P = 220 * 220 / 1500 = 32.27 Ω
The rated voltage is 40V, and the working current is 5V. If the electric appliance is connected to the lighting circuit of 220V, how to connect the resistance of many ohm
36 Ω resistance shall be connected in series;
Because the rated voltage is only 40V, if it is burned in parallel, it can only be in series;
Series resistance: r = (220-40) / 5 = 180 / 5 = 36 Ω
How does the total resistance of a home circuit change when all the appliances are working
The total resistance of a home circuit varies with the operation of all appliances
The total resistance of the home circuit becomes smaller when all the electrical appliances are working. This is because all the electrical appliances in the home circuit are in parallel. The more the resistance is, the smaller the total resistance will be. Moreover, it is smaller than the smallest one
Please remember:
Resistance: the greater the string, the greater the maximum resistance;
The smaller the resistance is, the smaller the minimum resistance is
When a household appliance works normally, the current passing through is about 5a, which may be ()
A. Television B. air conditioner C. incandescent lamp D. washing machine
The rated voltage of household appliances are all 220 v. according to P = UI, the electric power of a and TV is about 100 W and the working current is about 0.5 A; the electric power of B and air conditioner is about 1000 W and the working current is about 5 A; the electric power of C and incandescent lamp is about 60 W and the working current is about 0.3 A; the electric power of D and washing machine is about 200 W and the working current is about 0.3 a
In parallel circuit, there are two consumers, one with large resistance and the other with small resistance. Will the current pass through the consumer with large resistance?
Will the resistance of one branch change while the current of the other branch change in parallel circuit?
Still, the current mainly passes through the path with small resistance. It can be understood that the small resistance is like a big gate, the large resistance is like a small gate, and the current is like water flow. It can't all pass through the big gate instantaneously, and water will still pass through the small gate. The calculation formula is as follows: if two resistors are connected in parallel, 1 / r = 1 / R1 + 1 / r2 = (R1 + R2) / R1
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