In a series circuit, when there are multiple electrical appliances, how does the current change when one resistance is constant and one resistance is increased? Is the current of series circuit determined by the large resistance? Or is the resistance small?

In a series circuit, when there are multiple electrical appliances, how does the current change when one resistance is constant and one resistance is increased? Is the current of series circuit determined by the large resistance? Or is the resistance small?

Smaller
U = I * r u is the voltage I is the current R is the resistance
The current in series circuit is equal, and the resistance is equal to the sum of the resistance of all electrical appliances
Then we can regard the series connected consumer as a resistor
Then it becomes larger, the power supply does not change, the current must be smaller

There is a light bulb, which is connected to a 36V circuit, and the current passing through is 0.5A when it works normally. It is found that there is a fault in the 36V circuit, so it needs to be connected to a 220V circuit to make it work normally. What is the resistance in series?

According to Ohm's Law: r = UI = 36v0.5a = 72 Ω. To make it work normally when connected to the circuit of 220 V, the voltage is 36 V and the current is 0.5A. The voltage on the connecting resistor is 220 v-36 v = 184 V and the current is 0.5A. According to Ohm's law: R0 = u1i = 184 v0.5a = 368 Ω. A: a 368 Ω resistor should be connected in series to make the lamp work normally