For every 2 Coulomb of electricity passed by an electric appliance, the working current is 440 joules If the current intensity in the circuit is known to be 0.2 a, find (1) the resistance of the appliance (2) the voltage at both ends of the power supply (3) the power of the appliance. I know that the first two answers are 1100 Ω and 220 V, but I won't do it. I will ask for the answer tonight

For every 2 Coulomb of electricity passed by an electric appliance, the working current is 440 joules If the current intensity in the circuit is known to be 0.2 a, find (1) the resistance of the appliance (2) the voltage at both ends of the power supply (3) the power of the appliance. I know that the first two answers are 1100 Ω and 220 V, but I won't do it. I will ask for the answer tonight

(1) T = power / I = 10s
R = work / (I * 2 T) = 1100
(2)U=IR=110
(3)P=I*2R=110

What is the decomposition unit of Joule?
Because we all know that joule is a coincidence unit. I want to know what it looks like when it is converted into international units. For example, if 1n = 1kg · M / S ^ 2, is the unit of Joule a composite unit of kg * m ^ 2 / S ^ 2? If not, what is it?

Joule is the international unit, but it is not the basic unit. People often use it to make regulations. The basic unit is only the length unit (m), the mass unit (kg), the time unit (s), the temperature unit (k), the current unit (a), the mass unit (mol) and the luminous intensity unit (CD)

1 Coulomb = how much electricity?
What I want to know is the equivalent of how many joules of energy

1 coulomb is how much electricity! This is like asking how many people a person is!
Because coulomb is the unit of electric quantity, so 1 coulomb is of course the electric quantity of 1 Coulomb!

When 3 coulombs of electricity passes through a consumer with a resistance of 2 ohm and the work done by the current is 15 joules, what is the current passing through the consumer?

W = I ^ 2rt = I * (it) * r = I * Q * r = 15, so I = 15 / (QR) = 15 / (3 * 2) = 2.5A