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How much is the power of an electrical appliance with 4 ohm resistance and 5 Coulomb of electricity per second?
Q = it = I × 1s = 5C
So I = 5A
U = IR = 5A × 4 Ω = 20V
P = UI = 20V × 5A = 100J
So the answer is 100 joules
The battery pack with electromotive force of 8V and internal resistance of 2 ohm is used to connect two resistance wires of 1 ohm each to supply power to the pure resistance and obtain 3 watts of electric power to calculate the current and voltage of the appliance
Verification: every two intersecting and non copoint four lines must be in the same product plane
Because 8-4i = u, 3 = UI, 4I & # 178; - 8i + 3 = 0, the voltage is 6V when the current is equal to 0.5A, and 2V when the current is equal to 1.5A
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