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Xiaoming pushes the car with a force of 10 N and a force of 50 N on the horizontal ground at a constant speed in a straight line, then (1) the friction force received by the car is n, (2) The car is supported by cattle
The car moves in a straight line with uniform speed, and the force in the horizontal direction is balanced
Friction = thrust = 10N
The car moves in a straight line with uniform speed, and the force in the vertical direction is balanced
Support force = gravity = 50N
When the car moves at a constant speed, a pair of interacting forces in the horizontal direction are equal
It's not balance
It's an interactive force
The friction of the car against the ground and the friction of the ground against the car. It is the same whether the speed is constant or not
The mass of the car is 5T, and the rated power is 30kW. (1) if the resistance of the car is 2000N when driving on the horizontal road, what is the maximum speed? (2) if the resistance remains unchanged, what is the actual power of the car when driving at 10m / s on the horizontal road?
(3) If the resistance remains the same, can the car run at a speed of 10m / s on a slope with an inclination of 10? (?) known as sin10? = 0.17)
Do you need the steps? It's troublesome to write the steps here. Write an answer first
（1）15m/s
(2) 20kw
(3) No
A car runs at a constant speed on the highway at a speed of 30m / s, and the resistance is 2000N. What is the work done by the car in one minute? What is the power of the engine?
Urgent! Please make it clear, because I don't quite understand this part
So the traction force is 2000 n,
W=FS=2000*(30*60)=3600000J
P=W/t=3600000/60=60000w
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