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A vehicle with a weight of 5 × 10 quartic power n drives at a speed of 36 km / h on a straight road for 3 km at a uniform speed, If the engine power of the car is 30kW during this journey, the (2) The size of the resistance of a car in motion
V=36km/h=10m/s
From P = FV, f = P / v = 30000 / 10 = 3000n
Resistance = f = 3000n due to uniform speed
A car with one or two 5 × 10 quartic oxen drives at a speed of 10 meters per second on a straight road at a constant speed of 2000 meters. It is known that the traction of the car engine is 3000 oxen in this section of the road. How much work does the car do on this section of the road
3000 * 2000 = 3000000j
A car runs at a constant speed of 30 m / s on a straight expressway, and its traction force is 2 * 10 cubic Newton
(1) The resistance of the car; (2) the distance of the car in five seconds; the work of the car in five seconds; (4) the power of the car
(1) So f = f = 2 * 10 ^ 3N
(2)S=v*t=150m W=F*S=3*10^5N
(3)P=W/t=6*10^4w
A car has been driving at a speed of 36km / h for 16S on a straight road
A car has been driving at a speed of 36km / h for 16S on a straight road. In this process, the work done by the car's traction force is 8.0 × 10 quartic joules?
1)
V=36km/h=10m/s
Power P = work / time = (8.0 * 10 ^ 4J) / 16S = 5 * 10 ^ 3W = 5KW
2)
P=FV
F=P/V=5000/10=500N
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