When a car with a mass of 2T moves in a straight line along a horizontal highway, the traction force on the car is 2000N and the resistance is 0.01 times of the weight of the car. The resultant force on the car is calculated. (G is 10N / kg)

When a car with a mass of 2T moves in a straight line along a horizontal highway, the traction force on the car is 2000N and the resistance is 0.01 times of the weight of the car. The resultant force on the car is calculated. (G is 10N / kg)

G = mg = 2000kg × 10N / kg = 2 × 104nf = 0.01g = 0.01 × 2 × 104n = 200nf = f-f = 2000n-200n = 1800n, the direction is the same as the direction of traction. A: the resultant force on the car is 1800n, the direction is the same as the direction of traction

If a car with a mass of 10 tons runs at a constant speed on the road, the traction force it receives is 0.2 times of the weight of the car, what is the resistance it suffers?

The mass of the car M = 10t = 1 × 104kg, the gravity of the car g = mg = 1 × 104kg × 9.8n/kg = 9.8 × 104n. Because the car runs at a constant speed, the friction resistance f = f = 0.2g = 0.2 × 9.8 × 104n = 1.96 × 104n. A: the resistance of the car is 1.96 × 104n

When a truck with a weight of 80000 n drives at a constant speed on a horizontal highway, the friction resistance it receives is 0.02 times of its weight. How much traction does the truck receive?

When a car with a mass of 2 tons moves in a straight line at a constant speed along a horizontal highway, the resistance of the car is 0.01 times of the weight of the car. Calculate the traction force of the car. (G is 10N / kg)

200N