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In △ ABC, ab = AC, BC = 6, angle BAC = 120 °, AB / BC can be obtained
From the sine theorem: BC / Sina = AB / sinc
6 / (denominator →) radical 3 / 2 = AB / (denominator →) 1 / 2
The root sign 3 / 2 (multiplied by) AB = 3
｜ AB = 2 (multiplied by) root 3
Ψ AB / BC = 2 (multiplied by) radical 3 / 6 = radical 3 / 3
Mobile party, I'm so tired!
Two vehicles a and B are facing each other from ab at the same time. After meeting, they continue to move forward and return immediately when they arrive at the two places. It is known that the distance between the first and second meeting points of the two vehicles is 70km, and the speed ratio of the two vehicles is 4:3?
4+3=7
3*3=9
9-7=2
4/7-2/7=2/7
70 / 2 / 7 = 245km
Party A and Party B walk in the same direction from the two places of AB at the same time. For the first time, they meet 70 meters away from a, and for the second time, they meet 80 meters away from B
The first time we met, Party A and Party B had a total journey, and Party A had a journey of 70 meters
In the second meeting, Party A and Party B made a total of three rounds, and Party A made a total of 70 × 3 = 210 meters, and at the same time, it was one round trip more than 80 meters
therefore
What is the distance between a and B
70 × 3-80 = 130m
The first time they met 80 meters away from B, they returned immediately after arriving at their destination, and the second time they met 40 meters away from a, they calculated the distance between a and B
The first time we met, the two cars walked twice the distance, and the second time we met, the two cars walked twice the distance
So the second time is twice as long as the first time
Suppose the car from point B is B, then B walked 80 meters when he first met
B after the first meeting, to the second meeting, he walked 80 * 2 = 160 meters (speed unchanged, time doubled)
160 = distance - 80 + 40
Distance between the two places = 160 + 80-40 = 200m
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