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A and B start from two places at the same time and travel in opposite directions. Car a travels 65 kilometers per hour and car B 60 kilometers per hour. The two cars meet at the midpoint of 15 kilometers. How many hours have the two cars met after they leave at the same time?
When meeting, car a travels 15 × 2 = 30 km more than car B, and car a travels 65-60 = 5 km / h faster than car B
15 × 2 ÷ (65-60) = 6 (hours)
A and B start at the same time from AB and run in opposite directions. A's speed is 75% of B's. when the two cars meet, they are 20km away from the midpoint of AB, and the distance between AB is calculated
The speed of a is 75% of that of B, and the distance of a's car is 75% of that of B's car
A car line is 75% of the whole journey (1 + 75%) = 3 / 7
The distance of AB is 20 (1 / 2-3 / 7) = 280 (km)
A and B are traveling from a and B at the same time. A travels 75 kilometers per hour and B 60 kilometers per hour. The two vehicles meet at 30 kilometers from the midpoint to find the distance between the two places
Let's meet in X hours
75x-60x=2*30
The solution is x = 4
So the distance between the two places is equal to (75 + 60) * 4 = 540
A and B start from the two cities of AB at the same time and run in opposite directions. They meet at 75 km away from city A. when they arrive at each other's city, they immediately return along the same road at the same speed, and then meet at 33 km away from city A. what is the distance between the two cities of AB?
Party A and Party B meet for the first time, a total of 1 journey
Among them, a has traveled 75 kilometers
Party A and Party B meet for the second time, totally 3 whole journey
Among them, a line of two, the whole minus 33 kilometers
Party A and Party B go through three whole courses, which takes three times as long as one whole course
A: 75 × 3 = 225 km
Whole journey (AB distance): (225 + 33) △ 2 = 129 km
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