Car a and car B start from AB and run in opposite directions. Car a runs 50 kilometers per hour and car B runs 60 kilometers per hour. Car B is delayed for one hour due to repair, The cars meet at C, 10km from the midpoint,

Car a and car B start from AB and run in opposite directions. Car a runs 50 kilometers per hour and car B runs 60 kilometers per hour. Car B is delayed for one hour due to repair, The cars meet at C, 10km from the midpoint,

According to the location where the two cars meet, whether they are close to a or B, there are two answers
(1) Assuming that the location of meeting is on the side close to a, the distance should be 820 km. In this way, a walks for 8 hours, and the distance is 50 * 8 = 400 km. B walks for 7 hours, and the distance is 60 * 7 = 420. B walks 20 km more than a. the distance between AB and a is 400 + 420 = 820 km
(2) Assuming that the location of the meeting is close to B, the distance should be 380 km. In this way, a walks for 4 hours, 50 * 4 = 200 km, B walks for 3 hours, 60 * 3 = 180, and a walks 20 km more than B. the distance between AB and B is 200 + 180 = 380 km
As for the process of solving the problem, we can assume that a's driving time is x, so B's driving time is (x-1), and then establish an equation for the difference between a and B's driving distance, get the time, and then calculate the distance
Generally, this kind of problem needs to be solved by drawing, which is more clear
Why don't you give me some points

Car a and car B start from a and B at the same time and travel in opposite directions. Car a travels 60 kilometers per hour, and car B travels 50 kilometers per hour. After meeting, the two cars continue to move at the same speed. After another three hours, car a arrives at place B. how many kilometers did car a travel when they met?

60 × 3 △ 50 = 3.6 (hours) 60 × 3.6 = 216 (kilometers) a: when we met, car a traveled 216 kilometers

The two trains leave from two stations at the same time. The speed of train a is 65km / h, and that of train B is 60km / h. they meet at 15m away from the midpoint to find the distance between the two stations

Car a runs 15 * 2 = 30 (thousand?) meters more than car B
Car a is 65-60 km / h faster than car B
30 / 5 = 6 hours
6 * (60 + 65) = 750 km in total

A and B want to travel from a and B respectively. A travels 65 kilometers per hour, B travels 60 kilometers per hour, and the two cars meet at the midpoint of 15 kilometers
A and B drive from a and B respectively. A runs 65 kilometers per hour and B 60 kilometers per hour. The two vehicles meet at the midpoint of 15 kilometers. How many kilometers is the distance between a and B?

15 × 2 ÷ (65-60) = 6 hours, so Party A and Party B meet after driving for 6 hours
6 × (65 + 60) = 750 km
A: the distance between AB and ab is 750 km