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The average speed of a car travelling between AB and ab is 45 kilometers per hour when it goes and 30 kilometers per hour when it comes back?
Let the distance between a and B be x, X / 45 from a to B and X / 30 from B to a. the total time is x / 45 + X / 30
The average speed is 2x / (x / 45 + X / 30) = 36 km / h
The fast and slow trains go from a to B at the same time. The fast train runs 54 kilometers per hour and the slow train 48 kilometers per hour. The fast train stops for 3 hours on the way. As a result, the two trains arrive at B at the same time. The distance between a and B is calculated
Let the fast train travel time be x hours, then the slow train travel time be x + 3 hours, & nbsp; & nbsp; & nbsp; 54x = 48 (x + 3) & nbsp; & nbsp; & nbsp; 54x = 48x + 14454x-48x = 48x + 144-48x & nbsp; & nbsp; & nbsp; & nbsp; 6x = 144 & nbsp; & nbsp; 6x △ 6 = 144 △ 6 & nbsp; & nbsp
If a car travels 54 kilometers per hour from place a to place B, it will arrive one hour earlier than the original time; if it travels 45 kilometers per hour, it will arrive one hour later than the original time, what is the distance between place a and place B?
(1 + 1) △ 145-154, = 2 △ 6270-5270, = 2 △ 1270, = 2 × 270, = 540 (km); a: the distance from place a to place B is 540 km
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