Party A and Party B respectively set out from two places AB at the same time and walk opposite each other. As a result, they meet 60 meters away from the midpoint of the two places. It is known that Party A travels 20% more than Party B to find the distance between the two places

Party A and Party B respectively set out from two places AB at the same time and walk opposite each other. As a result, they meet 60 meters away from the midpoint of the two places. It is known that Party A travels 20% more than Party B to find the distance between the two places

If the distance of line B is regarded as unit 1, then:
(1) 60 meters is 20% of unit 1, so the distance of B line is
60 / 20% = 300 m
(2) The distance of line a is 300 * (1 + 20%) = 360 meters
(3) The distance between AB is 300 + 360 = 660 meters

A and B two cars from AB two opposite, two cars meet at 50km from the midpoint, a travel 30km per hour, B travel 20% more than a per hour, find the distance between AB two places

30÷【1/2-1/（1+1+20%）】
=30÷【1/2-5/11】
=30÷1/22
=660km

A and B vehicles run from two places at the same time. Car a runs 45 kilometers per hour and car B runs 42 meters per hour. The two vehicles meet at the midpoint of 12 kilometers
How many hours after two cars leave at the same time? (don't use equation)

12*2/(45-42)=8

The distance between a and B is 20 kilometers. A and B walk from a and B at the same time. Two hours later, they meet. After meeting, a returns to a, and B still advances to A. when a returns to a, B is still 2 kilometers away from A. suppose that the speed of a and B is respectively x km / h and Y km / h, then the equations can be formulated as follows

{ 2(x+y)=20
{ 4x - 4y =2