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The speed ratio of car a to car B is 5:3. Car a runs more than 2 / 5 of the whole journey, 36km, and just meets car B. how many kilometers is the distance between car a and car B?
The speed ratio of the two vehicles is 5:3
So when a goes 5 / (5 + 3) = 5 / 8, the two cars meet
So distance = 36 / (5 / 8-2 / 5) = 60 km
A and B set out from a and B to face each other. A set out for one hour first, and they met after four hours. It is known that a travels 2 kilometers more per hour than B, and the meeting place is 10 kilometers away from the midpoint of AB, so AB is far away from each other______ Kilometers
10 × 2-2 × 4 = 20-8 = 12 (km) (12-2 + 12) × 4 + 12 = 22 × 4 + 12 = 100 (km) answer: AB is 100 km away from each other
A and B start from ab at the same time and travel in opposite directions. They plan to meet in 6 hours. However, car a travels 3 kilometers more per hour than the original plan, and car B travels 1 kilometer less than the original plan. As a result, they meet in 5 hours. How many kilometers is the distance between AB and B
Let the distance between a and B be unit length "1", then
The planned speed sum of a and B cars is 1 / 6
The sum of the actual speeds of a and B vehicles is 1 / 5;
The distance between the two places is:
（3-1）/(1/5-1/6)
=2/(1/30)
=60km
A and B start from a and B at the same time and face each other, and meet at point C after 5 hours. If a's speed remains the same, B travels 4 kilometers more per hour, and a and B start from a and B at the same time and face each other, then the meeting point D is 10 kilometers away from point C. if the original speed ratio of a and B is 11:7, how many kilometers per hour is a's original speed?
If the speed of a is x, then the speed of B is 711 x, then the distance a passes through for the first time is 5 x, and the distance b passes is 5 × 7 x 11. If the speed of B increases to 7 x 11 + 4 for the second time, then the distance a passes through before meeting is 5 X-10, and the distance b passes is 5 × 7 x 11 + 10, then the time a takes before meeting is 5 x − 10 X
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