Ship a and ship B are facing each other at the same time from two docks 384 kilometers apart. Ship a is traveling 21 kilometers per hour, and ship B is traveling 27 kilometers per hour? (solution of equation)

Ship a and ship B are facing each other at the same time from two docks 384 kilometers apart. Ship a is traveling 21 kilometers per hour, and ship B is traveling 27 kilometers per hour? (solution of equation)

Let two ships meet in X hours. According to the meaning of the question, 21x + 27x = 384, & nbsp; & nbsp; & nbsp; 48x = 384, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 8. A: the two ships meet in 8 hours

A and B leave each other from two docks with a distance of 105km at the same time. Ship a travels 20km per hour, while ship B travels 15km per hour. How many hours later will they meet?

The sum of the velocities is 20 + 15 = 35
The meeting time is 105 △ 35 = 3 hours

At the same time, Party A and Party B depart from a and B ports and travel back and forth. Party A travels 30 kilometers per hour and Party B 40 kilometers per hour
Ship B has traveled 45 kilometers more than ship A. how many kilometers are there between ports a and B

At the second meeting, ship B traveled 45 kilometers more than ship a,
At this time, the departure time has passed 45 (40-30) = 4.5 hours;
When they met for the second time, they made a total of three journeys,
It can be concluded that the distance between ports a and B is (40 + 30) × 4.5 △ 3 = 105 km

A and B leave each other, and meet at 18km away from the midpoint. The speed ratio of a and B is 7:6. How many km is the distance between a and B

Let the speed of car a and car B be 7V and 6V respectively
Then 7v-6v = 18 × 2
v=36
7v+6v
=13×36
=468 km
So: the distance between a and B is 468 km