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A and B start from ab at the same time by bicycle, and walk towards each other. When they meet, they are 2.4km away from the midpoint of the two places, and only a's speed is twice that of B. how many kilometers is the distance between AB and B?
Let the velocity of B be V, then the velocity of a is 2V, and the distance between AB and B is s
（2V+V）*t=S
2V*t=S/2+2.4
The solution is s = 14.4km
The speed of a is 11km / h, and the speed of B is 9km. When they meet, they are 2km away from the midpoint
How many kilometers away?
2 × 2 ÷ (11-9) = 2 hours (encounter time)
Whole journey = (11 + 9) × 2 = 40 km
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