Twenty five percent of a pile of coal was used up, and then 18 tons of coal came in, five percent more than before. How much coal was there?
Suppose there were x tons of coal
3/4 *x+18=1.05*x
So it's a good solution
X = 60 (ton)
After 72% of a pile of coal is used up, 18 tons are transported in. At this time, it is 8% more than the original. How many tons of this pile of coal are there?
No equations
18 / (72% + 8%) = 22.5 tons
This pile of coal is 22.5 tons
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