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Party A and Party B have 260 kg of oil in total. Party a poured 20% of the oil to Party B. after pouring, the ratio of oil between Party A and Party B was 6:7, and Party A had several thousand grams of oil?
After pouring:
A: 260 △ 6 + 7 X6 = 120 (kg)
A: 120 (1-20%) = 150 (kg)
A barrel of oil is 3.6kg more than B barrel. If 1kg oil is poured out from each barrel, the remaining 2 / 21 of a barrel is equal to the remaining 1 / 7 of B barrel. How much oil does a barrel have
If two barrels of oil are poured out by 1kg each, there will be XKG left for B and (x + 3.6kg) left for a
1/7X=(X+3.6)(2/21)
X=7.2
A: Oil: 7.2 + 1 + 3.6 = 11.8kg
For a pile of coal, two fifths of the total amount and four ninths of the total amount are used first. At this time, 31 tons more than the rest are used. How many tons are there in this pile of coal? Solve the equation
Be clear,
If the weight of the pile of coal is a, then 3 / 5 × a + 4 / 9 × a = 21, then the final calculation result is a = 20.11 (approximate)
Hope to solve your problem
One fourth of the total amount of coal is used up, another one fourth of a ton is used up, and one fourth of a ton is left. This pile of coal used to be () tons
There was
（1/4+1/4）÷（1-1/4）
=1/2÷3/4
=1/2x4/3
=2 / 3 tons
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