The total weight of coal in pile a and pile B is 35 tons. If 15 tons are used in each pile, there are 12 tons left in pile a and how many tons left in pile B?

The total weight of coal in pile a and pile B is 35 tons. If 15 tons are used in each pile, there are 12 tons left in pile a and how many tons left in pile B?

12 (1-15) = 12 (1-15) = 45, = 15 (tons); (35-15) × (1-15), = 20 × 45, = 16 (tons)

The total weight of coal in pile a and pile B is 35 tons. If 5 / 1 of each coal is used, there will be 12 tons left in pile a and how many tons left in pile B?

12 ÷ (1-1 / 5) = 15 tons
Residual B (35-15) x (1-1 / 5) = 16 tons

The total weight of coal in pile a and pile B is 35 tons. If 15 tons are used in each pile, there are 12 tons left in pile a and how many tons left in pile B?

12 (1-15) = 12 (1-15) = 45, = 15 (tons); (35-15) × (1-15), = 20 × 45, = 16 (tons)

The total weight of coal in pile a and pile B is 35 kg. If 1 / 5 of each coal is used, there are 12 tons left in pile a, then how many tons are left in pile B

There are 4 / 5 left in pile a and 12 * 5 / 4 = 15 in pile a
There are 20 tons in reactor B, and the remaining 4 / 5 120 * 4 / 5 = 16 tons
A: there are 16 tons left
I wish you progress in your study!

The total weight of coal in pile a and pile B is 35 tons. If 15 tons are used in each pile, there are 12 tons left in pile a and how many tons left in pile B?

12 (1-15) = 12 (1-15) = 45, = 15 (tons); (35-15) × (1-15), = 20 × 45, = 16 (tons)

The canteen carries in a batch of coal. It is planned to burn 0.3 tons a day, which can last 20 days. If 0.25 tons a day, how many days can it last? First of all, please ask:?

The total tonnage of this batch of coal is: 0.3 × 20 = 6 (tons), 6 △ 0.25 = 24 (days); a: it can burn for 24 days. So the answer is: how many tons of this batch of coal are there in total

There is a batch of coal in a factory. The original plan is to burn 0.25 tons per day, which can burn for 100 days. In fact, the daily coal consumption is 20% less than the original plan. How many days can we actually burn?

The total tons of this batch of coal: 0.25 × 100 = 25 (tons), the actual tons burned every day: 0.25 × (1-20%) = 0.25 × 0.8 = 0.2 (tons), the actual days burned: 25 △ 0.2 = 125 (days); a: it can actually burn for 125 days

The canteen bought a batch of coal and planned to burn 0.25 tons a day for 20 days. In fact, it saved 20% every day compared with the original plan. How many days can be saved?
Using the proportion equation to solve the problem

Suppose you can burn for X days
1：（1-20%）=x：20
x=20÷80%
x=25
If you don't understand this question, you can ask,

There is a pile of coal in a factory. Originally, it was planned to burn 0.25 tons of coal per day for 100 days. Actually, it burns 0.2 tons per day. How many days more than planned?

0.25 × 100 △ 0.2, = 25 △ 0.2, = 125 (days); 125-100 = 25 (days); a: This is 25 days more than the plan

There is some coal in the factory. It was originally planned to burn 5 tons a day for 60 days. Due to the improvement of coal burning technology, it can save 20% a day compared with the original plan. How many days can it be reduced now（

Now you can burn 60 * 5 / [5 * (1-20%)] = 75 days