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A batch of coal is transported to a power plant. It was originally planned to burn 10 tons of coal every day, but it is finished in 36 days. Actually, it saves 10% of coal every day. How many days can it burn
It's supposed to burn for X days
X*10*(1-10%)=10*36
9X=360
X=360/9
X=40
It can be burned for 40 days
The canteen transported 23 tons of coal. After 14 tons were used, the remaining 13 tons were used. How many tons were used?
(23-14) × 13 = 512 × 13 = 536 (tons) a: another 536 tons will be used
Take 2 / 7 of the coal from pile a to pile B, and the weight of the two piles of coal is equal. The original weight ratio of pile a and pile B is () a7:5 b9:7 c7:3
A (1-2 / 7) = 2 / 7 A + B
3 / 7 A = b
A: B = 7:3
The total weight of the two barrels of oil is 260 kg. If one eighth of the oil in barrel a is poured into barrel B, the mass ratio of barrel a and barrel B is 7:6. How much oil are the two barrels
260 ÷ (7 + 6) × 7 = 140 kg
140 ÷ (1-1 / 8) = 160 kg
260-160 = 100 kg
A barrel had 160 kg, B barrel had 100 kg
A and B have two barrels of oil, and a has 10 kg of oil. If 12 barrels are poured from a barrel to B barrel, then the ratio of a and B is 1:7. How much oil is there in the two barrels?
10 × (1-12) + 10 × (1-12) △ 1 × 7 = 10 × 12 + 10 × 12 △ 1 × 7 = 5 + 5 × 7 = 5 + 35 = 40 (kg) a: two barrels used to have 40 kg of oil
The mass ratio of a and B barrels of oil is 4:1. After 130 kg is taken from a barrel and put into B barrel, the mass ratio of a and B barrels of oil is 7:5?
480kg~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
There are two barrels of oil a and B. after 15L of barrel a oil is injected, the quality of the two barrels of oil is equal. If 145l of barrel B oil is injected, the quality of barrel B oil is three times that of barrel a
Now find the original quality of two barrels of oil
A barrel of oil x liter, B barrel of oil y liter
x+15=y
3x-y=145
3x-(x+15)=145
2x=145+15
x=80
y=x+15
y=80+15
y=95
If there are two barrels of oil a and B, the quality of the two barrels will be equal after 15 liters of barrel a oil is injected; if 145 liters of barrel B oil is injected, the quality of barrel B oil will be three times that of barrel a oil,
A: (145 + 15) / (3-1) = 80
B: 80 + 15 = 95
A and B two barrels of oil, from a barrel of oil into 15L and B barrel of oil equal, to B barrel of oil into 145l, B barrel of oil is three times as much as a barrel of oil, two barrels of oil each how many l?
One yuan to the power
Let a be x and B be x + 15
X+15+145=3X
Solution
X=80
B is x + 15 = 95
There are two barrels of oil a and B. after 15 liters of oil is injected into barrel a, the two barrels have the same mass. If 145 liters are injected into barrel B, then barrel B is three times as much as barrel a
How many liters each of the original two barrels of oil
A = (145 + 15) / (3-1) = 80 liters;
B = 80 + 15 = 95 liters
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