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The goods quality ratio of warehouse A and warehouse B is 7:5. After 650 tons of goods are transported from warehouse A to warehouse B, the goods quality ratio of warehouse A and warehouse B becomes 3:4, and the original value of warehouse A is calculated
Set warehouse a x, warehouse B 5 / 7X
（x-650)/(5/7x+650)=3/4
x=2450
The tonnage ratio of warehouse A and warehouse B is 7:5. After 650 tons of goods are transported from warehouse A to warehouse B, the tonnage ratio of the two warehouses becomes 3:4. Excuse me, how many tons of goods were there in warehouse a?
Let a be 7x tons and B be 5x tons, then there is an equation
（7X-650）/(5X+650)=3/4
15X+1950=28X-2600
13X=4550
X=350
A: 7 * 350 = 2450 tons
B: 5 * 350 = 1750 tons
The tonnage ratio of the two warehouses of a and B is 7:5. After 650 tons are transported from a to B, the tonnage ratio of the two warehouses is 3:4
There are x tons of goods in warehouse A and Y tons of goods in warehouse B
X/Y=7/5
（X-650)/(Y+650）=3/4
Remove the equations
X=2450
A: the original cargo is 2450 tons
The weight ratio of goods in warehouse A and warehouse B is 7:5. If warehouse A gives 26 tons to warehouse B, then the weight ratio of goods in warehouse A and warehouse B is 3:4. How many goods does warehouse a have?
Suppose the weight of goods in warehouse A is 1 / 7 and the weight is X
(7X-26)/(5X+26)=3/4
X=14
Weight of goods in warehouse a = 7x = 98
B warehouse cargo weight = 5x = 70
In the two warehouses, the weight ratio of the stacked goods is 3:7. After 9 tons are transported into warehouse A and 4 tons are transported out of warehouse B, the weight ratio of the stacked goods of warehouse A and warehouse B is 3:5?
Suppose that warehouse a originally stored x tons of grain, the meaning of the question is: & nbsp; X + 9 = 35 (73x-4) & nbsp; X + 9 = 1.4x-2.40.4x = 11.4 & nbsp; X = 28.573x = 73 × 28.5 = 66.5 answer: warehouse a originally stacked 28.5 tons of goods; warehouse B originally stacked 66.5 tons of goods
The mass ratio of a and B bags of rice is 7:5. If 12 kg rice is taken from a bag and put into B bag, then the two bags of rice are the same weight?
A 84
B 60
Primary school math problem: the original weight ratio of a and B bags of rice is 7:3. Pour 12 kg from a bag to B bag. At this time, the two bags of rice are the same weight, B bag is
Primary school math problem: the original weight ratio of a and B bags of rice is 7:3. Pour 12 kg from a bag to B bag. At this time, the two bags of rice are the same weight. How many kg is the original rice in B bag?
Suppose that the original weight of a bag of rice is 7x, and that of B bag is 3x,
7x-12=3x+12
4x=24
x=6
Bag B original rice 3x = 18 kg
The weight ratio of a and B bags of rice is 4:1. If 13 kg is taken from a bag and put into B bag, the weight ratio of a and B is 7:5, how many kg are there?
I want formula, not equation
1 / (1 + 4) = 1 / 5 of the total weight
Now B accounts for 5 / (5 + 7) = 5 / 12 of the total weight
The total weight is 13 (5 / 12-1 / 5) = 60 kg
B: 60x1 / 5 = 12kg
A originally weighs 60-12 = 48 kg
The weight ratio of package a and package B is 4:1. If 13 grams are taken from package a and put into package B, the weight ratio of package a and package B becomes 7:5, then what are the weights of the two packages?
Total weight: 13 △ 44 + 1-77 + 5, = 13 △ 45-712, = 13 △ 1360, = 60 (kg); a: 60 × 45 = 48 (g), B: 60 × 15 = 12 (g). Answer: the original caramel is 48 g, caramel is 12 G
Both granaries A and B store rice, which is 91.2 tons less than that in warehouse B. 35% of the rice stored in warehouse A and 65% of the rice stored in warehouse B are taken out
At this time, the weight of rice stored in the two warehouses is exactly the same. How many tons of rice was stored in warehouse a
Take out 35% of the stored rice from warehouse A and 65% of the stored rice from warehouse B. at this time, the weight of rice in the two warehouses is exactly the same
It is known that a × (1-35%) = B × (1-65%) a: B = 7:13
The original storage of rice in warehouse A is 91.2 ÷ (13-7) × 7 = 106.4 tons
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