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It is planned to transport a batch of coal in 10 days. In fact, it will transport 20 tons more per day. In this way, the task will be completed two days in advance. How many tons of coal are there Better not use equations
The original plan is to transport coal every day:
20 × (10-2) △ 2 = 80 tons
Original planned daily coal transportation × original planned days = total coal quantity
80×10=800
There are 800 tons of coal
To transport a batch of coal, if 10% more than planned, it can be transported one day ahead of schedule. If 6 tons less than planned, the transportation time will be one fourth more than planned. How many tons in total
Every day is 10% more than the plan, 10 days is more than one day's quantity, so the original plan is 11 days. 1 △ 10% = 10 days, 10 + 1 = 11 days. 6 tons less than the plan, 11 × 1 / 4 = 11 / 4 days more than the plan, a total of 11 + 11 × 1 / 4 = 55 / 4 days. 6 tons less than the plan, 55 / 4 × 6 less than the plan
Party A and Party B work together to complete a batch of parts in 6 hours. Now Party B will work for 1.5 hours first, and Party A will work together again. It will take 3 / 5 more hours to complete the task than planned?
Party A and Party B have cooperated
6+3/5-1.5
=6.6-1.5
=5.1 hours
B efficiency (1-1 / 6x5.1) △ 1.5 = 3 / 20 △ 3 / 2 = 1 / 10
A alone 1 (1 / 6-1 / 10) = 15 days
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Party A and Party B work together to complete a batch of parts in six hours. Now Party B works for 1.5 hours first, and Party A joins in the cooperation. It takes three fifths more to complete the task than planned
It is known that a makes 54 parts per hour. How many parts are there in this batch
Let B make x parts per hour, a total of Y parts
Then 6 (54 + x) = y;
1.5x + (4.5 + 0.6) (54 + x) = y; / / 0.6 = 3 / 5
The result is x = 81, y = 810
So there are 810 parts
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