In the plane rectangular coordinate system, given that point a (2,0), point B (4,0) and point C are on the Y axis, if the area of triangle ABC is 5, find the coordinate of point C

In the plane rectangular coordinate system, given that point a (2,0), point B (4,0) and point C are on the Y axis, if the area of triangle ABC is 5, find the coordinate of point C

If the coordinate (0,5) AB distance of point C is 2, the height of triangle ABC is 5. Or (0, - 5)

Triangle ABC in the plane rectangular coordinate system, known a (- 4,1) B (- 1, - 1) C (- 3,2) proof: triangle ABC is isosceles triangle
The proof is isosceles triangle

Have you learned vector? From the question, we can see: vector AB = (3, - 2), so | ab | = radical 13, and vector BC = (2,3), so | BC | = radical 13, so the length of AB side is equal to BC side, so triangle ABC is isosceles triangle

Given that there are two points a (- 2,1) and B (2,3) in the plane rectangular coordinate system, find a point C on the x-axis to minimize the perimeter of the triangle ABC, then the coordinate of point C is

The symmetric point of point a about X axis is a '(- 2, - 1)
If a'B and X axis intersect at C, then the perimeter of triangle ABC is the smallest
Let the analytic expression of a'B be y = KX + B
Substituting point a '(- 2, - 1) B (2,3) into
-2k+b=-1
2k+b=3
The solution is k = 1, B = 1
y=x+1
When y = 0, x = - 1
C(-1,0)