Like the faucet, the wheel and shaft are fixed together to rotate the machine, called ()

Like the faucet, the wheel and shaft are fixed together to rotate the machine, called ()


Like the faucet, the wheel and shaft are fixed together and can rotate. It is called (axle)



A common screw driver, it can be seen as an axle_____ It's his equivalent_____ What's the advantage of using it__


A common screw driver can be regarded as an axle. Its blade is equivalent to the axle, and its handle is equivalent to the wheel. Its advantage is that it can save labor
Baidu Encyclopedia has detailed information about wheel axles



If the centripetal force of an object in uniform circular motion suddenly decreases, what will happen to the motion state and how will the radius change? Please analyze


Centripetal force F = mrw2
When f decreases, the centripetal force is insufficient to provide motion, and finally the radius increases in circular motion
Teachers of Taiyuan Ziqiang school



The error in the following statement about uniform circular motion is ()
A. Constant linear velocity B. constant angular velocity C. constant period D. constant centripetal force


In uniform circular motion, the magnitude and direction of the center line velocity remain unchanged, the magnitude and direction of the angular velocity remain unchanged, the period remains unchanged, the magnitude of the centripetal force remains unchanged, and the direction always points to the center of the circle. It can be seen that the direction always changes. Therefore, D is wrong, and a, B and C are correct



As shown in the figure, we know that the masses of binary stars a and B are M1 and M2 respectively, and the distance between them is r


Centripetal force provided by gravitation of double stars
Gm1m2/r^2=m1ω^2r1 1
Gm1m2/r^2=m2ω^2r2 2 r1+r2=r 3
m1ω^2r1 =m2ω^2r2 m1r1 =m2r2 4 r2=(m1+m2)r/m1
Gm1m2/r^2=m14π^2r2/T^2 T= 2π( m1+m2)r^3/ Gm1m2)^1/2
From v = 2 π R / T, VI = [GM1 (M1 + m2) / m2 * r] ^ 1 / 2 V2 = [GM2 (M1 + m2) / M1 * r] ^ 1 / 2



A. The distance between two places B is s, the speed of the first half of a's journey from a to B is V1, the speed of the second half is V2 (V1 ≠ V2), the speed of the first half of B's journey from a to B is V1, and the speed of the second half is V2, then the relationship between the average speed of a and the average speed of B is v


The result of simplification can be remembered as a formula to save time in the future. This kind of problem has another form, that is: if the speed of the first half of the time is V1, and the speed of the second half is V2, it is also called to calculate the average speed, Then the average velocity (V1 + V2) / 2 & nbsp;
This is my answer to another similar question. The website is: http://zhidao.baidu.com/question/188476444.html  You can have a look, and then you can compare and solve your problems. I won't give you the final answer. It's better for you to do it yourself. If you really need it, hi me



If two stars with mass of M1 and M2 form a binary star, and the distance between the two stars is l, the period of constant motion of the binary star can be calculated


Let the radius of rotation of M1 be R1, then the radius of rotation of M2 is R2,
Gravity provides centripetal force,
Gm1m2/L^2=m1(2π/T)^2r1 ①
Gm1m2/L^2=m2(2π/T)^2r2 ②
From (1) and (2), we can get m1r1 = m2r2 and (3)
And R1 + R2 = L 4
R1 = m2l / (M1 + m2)
Substituting (1)
T=2π√[L^3/G(m1+m2)]



Know M1, M2, distance L, G, find the linear velocity V1, V2


V1=M2(G/(M1+M2)L)^1/2
V2=M1(G/(M1+M2)L)^1/2
If the angular velocity W is the same, the key is to find the center of mass
G*M1*M2/L^2=(M1+M2)M1*V1^2/(M2*L)
G*M1*M2/L^2=(M1+M2)M2*V2^2/(M1*L)
We can get V1, v2



Why are the orbital radius and linear velocity inversely proportional to their mass in the physical binary model


Because in the binary model, gravitation acts as the centripetal force of the two. The two gravitations are equal to each other, so the centripetal force is equal
Therefore, m1r1 ω 2 = m2r2 ω 2, because the two stars are equal, so m1r1 = m2r2, we can get R1 / r2 = m2 / M1. That is, the orbit radius is inversely proportional to the mass. And because the angular velocity is equal, so the linear velocity v = R ω, v1 / V2 = R1 / r2 = m2 / M1, that is, the linear velocity is also inversely proportional to the mass



Excuse me, on the earth, gravity provides gravity and centripetal force. What does gravity provide in the orbit above the earth (satellite)?
The orbit above the earth (satellite), how does gravity provide gravity and centripetal force to the satellite?


In fact, strictly speaking, among gravity, centripetal force and universal gravitation, only universal gravitation is the actual force, while gravity and centripetal force are the effect force. Therefore, when making force analysis, objects should only be subjected to universal gravitation. Why is it usually analyzed as gravity? That's because we ignore the rotation of the earth (the rotation of the earth is too slow, completely