The function f (x) = LNX + 3x-11 must have zero point () A. （0，1）B. （1，2）C. （2，3）D. （3，4）

When x = 1, 2, 3, 4, the function value y = - 8, ln2-5, ln3-2, 1 + ln4. According to the judgment theorem of zero point, we know that the zero point of function exists in (3, 4), so we choose D

Given | A-4 | + B & # 178; + 4 = 4b, find the value of a & # 178; - AB △ A & # 178; - B & # 178

|a-4|+b²+4=4b
|a-4|+b²-4b+4=0
∴|a-4|+(b-2)²=0
∴a-4=0
b-2=0
∴a=4
b=2
(a²-ab)÷(a²-b²）
=a(a-b)/(a+b)(a-b)
=a/(a+b)
=4/(4+2)
=2/3

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