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The three sides of a triangle are 4A + 5,2a-1,20-a, where a is an integer. To find the perimeter of the triangle, use the inequality If good, enough!
The sum of the two sides of a triangle is greater than the third side
4a+5+2a-1>20-a--->a>16/7
4a+5+20-a>2a-1--->a>-26
2a-1+20-a>4a+5--->a0--->a>1/2
20-a>0--->a
Given that a and B are the new sides of an isosceles triangle and satisfy a * + b * - 4a-6b + 13 = 0, find the new perimeter of the isosceles triangle
a²+b²—4a—6b+13=0
a²-4a+4 +b²-6b+9=0
(a-2)²+(b-3)²=0
Then a = 2, B = 3
Perimeter = 2 + 2 + 3 = 7 or 2 + 3 + 3 = 8
The two sides of a triangle are a + B and 2a-b respectively. The perimeter of the triangle is 4A + 1 / 2 times B. If a is greater than B, find the length of the third side of the triangle,
When a = 3, B = 2, write the length of each side of the triangle
Big brother, big sister,
5 4
Put a and B in
One side is a + B = 3 + 2 = 5
The other side is 2a-b = 2 * 3-2 = 4
My God, it's 1 / 7 in circumference
How to do it? I don't know. I'm sorry
Factorization of 4A ^ 2-9a ^ 2
Such as the title
Square difference
The original formula = (2a + 3b) (2a-3b)
RELATED INFORMATIONS
- 1. The square of polynomial 4x, the cube of y-5x, the cube of Y + the cube of 7xy-6 / 7 are arranged according to the descending power of X
- 2. The polynomial 4x ^ 2y-5x ^ 3Y ^ 2 + 7xy ^ 3-6 / 7 is arranged by the descending power of X and by the ascending power of Y
- 3. Decomposition factor: 20A (a-2b) ^ 2-12 (a-2b) ^ 3, where a = - 9, B = 3
- 4. Given a = {x | x2 + ax + B = 0}, B = {x | x2 + CX + 15 = 0}, a ∪ B = {3,5}, a ∩ B = {3}, find the value of real numbers a, B, C
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- 10. Calculate [(A-1) square - (1 + a) square] / (- 2A) [(A-1) - (1 + a)] / (- 2A) calculation
- 11. If the square of a plus the square of B minus 4A plus 6B plus 13 equals 0, find the square of a plus the square of B
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