Are two triangles with equal perimeter and area congruent?
Of course not!
If the perimeter and area of two triangles are equal, are they congruent~~~
Triangle 1: perimeter 18, three sides 8, 5, 5, area = √ [9 (9-8) (9-5) 178;] = 12
Triangle 2: perimeter 18. Trilateral length 6,6 + √ 33 / 3,6 - √ 33 / 3, area = √ [9 (9-6) (9-6 - √ 33 / 3) (9-6 + √ 33 / 3)] = 12
Obviously these two triangles are not congruent
If the perimeter and area of two isosceles triangles are equal, then are the two triangles congruent
Note: the perimeter and area of two isosceles triangles are equal
It's better not to ask that you're similar, isn't it? If not, please give a counter example
An isosceles triangle is provided, the bottom of which is a, the waist length is B, the height is h, the circumference is x, and the area is y
Where x and y are constants
Then a * H = 2Y
a+2b=x
h^2+(a/2)^2=b^2
Only the unique normal solutions of a, B and H are obtained by solving the equation
So it is proved