Are two triangles with equal perimeter and area congruent?

Are two triangles with equal perimeter and area congruent?

Of course not!

If the perimeter and area of two triangles are equal, are they congruent~~~

Triangle 1: perimeter 18, three sides 8, 5, 5, area = √ [9 (9-8) (9-5) &# 178;] = 12
Triangle 2: perimeter 18. Trilateral length 6,6 + √ 33 / 3,6 - √ 33 / 3, area = √ [9 (9-6) (9-6 - √ 33 / 3) (9-6 + √ 33 / 3)] = 12
Obviously these two triangles are not congruent

If the perimeter and area of two isosceles triangles are equal, then are the two triangles congruent
Note: the perimeter and area of two isosceles triangles are equal
It's better not to ask that you're similar, isn't it? If not, please give a counter example

An isosceles triangle is provided, the bottom of which is a, the waist length is B, the height is h, the circumference is x, and the area is y
Where x and y are constants
Then a * H = 2Y
a+2b=x
h^2+(a/2)^2=b^2
Only the unique normal solutions of a, B and H are obtained by solving the equation
So it is proved