If the squares of | A-2 | and (a + 2b) are opposite to each other, then the square of B is divided by 2=

If the squares of | A-2 | and (a + 2b) are opposite to each other, then the square of B is divided by 2=

If the numbers are opposite to each other, they add up to 0
|a-2|+(a+2b)²=0
Absolute sum of squares is greater than or equal to 0
If one is greater than 0, then the other is less than 0
So both are equal to zero
So A-2 = 0, a + 2B = 0
a=2
b=-a/2=-1
So B & sup2; △ 2 = 1 / 2

Given a + B = 2009, find the square of a + the square of B + 2b-1 / (the square of a - the square of B) + the value of a + B

a²-b²+2b-1/（a²-b²）+a+b
=（a²-b²+a+b+b-a-1）/(a+b)（a-b+1）
=1-1/(a+b)
=2008/2009

Given that a and B satisfy the following conditions: the square of a + 2 * the square of B - 2Ab - 1 = 0, find the value of a + 2B

The original formula is (a-b) ^ 2 + B ^ 2-1 = 0
Then A-B = 0, B ^ 2-1 = 0
Then a = b = 1
a+2b=3

A (1-2b) 2 + (a-b) (a + b) - 2 (a-3b) (a-b), where = 1 / 2, B = - 3

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