![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
As for the coefficient and degree of the monomial - π AB2, the following statement is correct: a. the coefficient is - 1, the degree is 4B. The coefficient is - 1, the degree is 3C. The coefficient is 0, the degree is 3D. The coefficient is - π, the degree is 3
According to the definition of monomial coefficient and degree, the number factor of the monomial - π AB2 is - π, and the sum of the exponents of all letters is 1 + 2 = 3, so its coefficient is - π and the degree is 3
RELATED INFORMATIONS
- 1. In the title, one person decomposes the factor 3x & # 178; YZ & # 178; - 6xyz & # 178; + 9xy & # 178; Z & # 178; to get 3xyz (XZ + 2Z + 3yZ), and another person says he is wrong. I think that's right. But according to international practice, this question should let me change the wrong one to the right one. If that's right, it must be wrong. Is it right or wrong?
- 2. If 4x & # 178; YZ & # 179; △ B = - 8x, then B =?
- 3. Simplification: C & # 178; (A & # 178; - B & # 178;) = (A & # 178; + B & # 178;) (A & # 178; - B & # 178;)
- 4. Given - M + 2n = 5, then 3 (m-2n) ^ 2 + 10n-5m-23?
- 5. F (x) = sin (n π - x) cos (n π + x) / cos ((n + 1) π - x) * Tan (x-n π) * cot (n π / 2 + x), find the value of F (π / 6)
- 6. Given that a and B are opposite numbers, B ≠ 0, m and N are reciprocal, and the absolute value of S is 3, the value of a / b (B of a) + Mn + s is obtained How to do this problem pinch? Who can tell me class?. 555. Urgent... Please!
- 7. It is proved that the necessary and insufficient condition for an image of a linear function y = - M / NX + 1 / N to pass through the first, second and fourth quadrants at the same time is Mn 〉 0 It is proved that the necessary and insufficient condition for an image of a linear function y = - M / NX + 1 / N to pass through the first, second and fourth quadrants at the same time is Mn 〉 0
- 8. As shown in the figure, we know that m (m, m ^ 2), n (n, n ^ 2) are two different points on the parabola C: y = x ^ 2, and m ^ 2 + n ^ 2 = 1, M + n ≠ 0, l is the vertical bisector of Mn Let the equation of ellipse e be x ^ 2 / 2 + y ^ 2 / a = 1 (a > 0, a ≠ 2) 1. When m and N move on the parabola C, find the value range of the slope k of the straight line L 2. It is known that line L and parabola C intersect at two different points a and B, and l and ellipse e intersect at two different points P and Q. let the midpoint of AB be r, and the midpoint of PQ be s. if vector or · vector OS = 0, the range of eccentricity of E can be calculated
- 9. Solving the equation mnx & sup2; - (M & sup2; + n & sup2;) x + Mn = 0 (Mn ≠ 0)
- 10. If m.n is the root of the linear equation with one variable, then m square n + Mn square - Mn =?
- 11. The coefficient degree of the monomial ab
- 12. Write out all 4-degree monomials with coefficients of - 2 and only letters A and B
- 13. If the monomial (- 1 / 7X ^ 3N + 2) y ^ 4 is the same as (5x ^ 8) y ^ 2m-2, then n = () M = ()
- 14. The following statements are correct: 1. The coefficient of 2x ^ 2Y is - 2, and the degree is 2.2. (A-1) B is a monomial. 3. X ^ 2 is a quadratic monomial. 4. X-2 is an integral
- 15. Write all the monomials with coefficient - 2, including the letters x, y and degree 4
- 16. Is 0 a monomial? What are the coefficients and times?
- 17. Can the coefficient in the monomial be 0?
- 18. The coefficient of monomial-1 / 3AB ^ 2
- 19. The coefficient a and the degree of monomial are respectively []
- 20. If - 2mx ^ NY is a quintic monomial about X, y and the coefficient is - 4, find the value of M, n