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Solving the equation mnx & sup2; - (M & sup2; + n & sup2;) x + Mn = 0 (Mn ≠ 0)
mnx² - (m² + n²)x + mn = 0
(mx -n)(nx -m) = 0
X = n / m or x = m / n
M / mx-n-2 / x = - N / NX + m (m ^ 2-N ^ 2 ≠ 0, Mn ≠ 0) to solve the equation
m/(mX-n)+n/(nX+m)=2/X
[m(nX+m)+n(mX-n)] / [(mX-n)(nX+m)]=2/X
(m^2-n^2+2mnX) / [(mn)X^2+(m^2-n^2)X-mn]=2/X
(m^2-n^2+2mnX) X=2[(mn)X^2+(m^2-n^2)X-mn]
(m^2-n^2)X-2mn=0
X=2mn/(m^2-n^2)
Solve the equation x & # 178; + MX NX Mn = 0 (m.n is nonzero)
x^2+(m-n)x-mn=0
(x+m)(x-n)=0
x=-m,n
RELATED INFORMATIONS
- 1. If m.n is the root of the linear equation with one variable, then m square n + Mn square - Mn =?
- 2. If (M + 2) x | m | - 1 + 8 = 0 is a linear equation with one variable, then M=______ ．
- 3. If M-N = - 3 Mn = 2, then (- 5m + 2) - 5 (2mn-n)= If M-N = - 3 Mn = 2, then (- 5m + 2) - 5 (2mn-n)=
- 4. If M = 2 - √ 3, n = √ 3 - √ 2, then the size relation of Mn is
- 5. If the equation MX + 3-nx − 3 = 8xx2 − 9 holds for any x (x ≠ ± 3), then Mn = () A. 8B. -8C. 16D. -16
- 6. If the equation MX + 3 − nx − 3 = 8xx2 − 9 holds for all real numbers x except ± 3, then the value of Mn is () A. 8B. -8C. 16D. -16
- 7. Given the function f (x) = ㏒ 1 / 2 [(1 / 2) ^ X-1], it is proved that the function f (x) increases monotonically in the domain of definition
- 8. Given Mn ^ 2 = - 5, find the value of - Mn (m ^ 3N ^ 7-m ^ 2n ^ 5-N)
- 9. Given that M is reciprocal to each other, find - 2 (mn-3m ^ 2) + (mn-m ^ 2) - 2mn-2
- 10. Given the length of the line Mn 6 points m (1. - 3) endpoint n, find the coordinates of N on X Need specific process
- 11. As shown in the figure, we know that m (m, m ^ 2), n (n, n ^ 2) are two different points on the parabola C: y = x ^ 2, and m ^ 2 + n ^ 2 = 1, M + n ≠ 0, l is the vertical bisector of Mn Let the equation of ellipse e be x ^ 2 / 2 + y ^ 2 / a = 1 (a > 0, a ≠ 2) 1. When m and N move on the parabola C, find the value range of the slope k of the straight line L 2. It is known that line L and parabola C intersect at two different points a and B, and l and ellipse e intersect at two different points P and Q. let the midpoint of AB be r, and the midpoint of PQ be s. if vector or · vector OS = 0, the range of eccentricity of E can be calculated
- 12. It is proved that the necessary and insufficient condition for an image of a linear function y = - M / NX + 1 / N to pass through the first, second and fourth quadrants at the same time is Mn 〉 0 It is proved that the necessary and insufficient condition for an image of a linear function y = - M / NX + 1 / N to pass through the first, second and fourth quadrants at the same time is Mn 〉 0
- 13. Given that a and B are opposite numbers, B ≠ 0, m and N are reciprocal, and the absolute value of S is 3, the value of a / b (B of a) + Mn + s is obtained How to do this problem pinch? Who can tell me class?. 555. Urgent... Please!
- 14. F (x) = sin (n π - x) cos (n π + x) / cos ((n + 1) π - x) * Tan (x-n π) * cot (n π / 2 + x), find the value of F (π / 6)
- 15. Given - M + 2n = 5, then 3 (m-2n) ^ 2 + 10n-5m-23?
- 16. Simplification: C & # 178; (A & # 178; - B & # 178;) = (A & # 178; + B & # 178;) (A & # 178; - B & # 178;)
- 17. If 4x & # 178; YZ & # 179; △ B = - 8x, then B =?
- 18. In the title, one person decomposes the factor 3x & # 178; YZ & # 178; - 6xyz & # 178; + 9xy & # 178; Z & # 178; to get 3xyz (XZ + 2Z + 3yZ), and another person says he is wrong. I think that's right. But according to international practice, this question should let me change the wrong one to the right one. If that's right, it must be wrong. Is it right or wrong?
- 19. As for the coefficient and degree of the monomial - π AB2, the following statement is correct: a. the coefficient is - 1, the degree is 4B. The coefficient is - 1, the degree is 3C. The coefficient is 0, the degree is 3D. The coefficient is - π, the degree is 3
- 20. The coefficient degree of the monomial ab