Given - M + 2n = 5, then 3 (m-2n) ^ 2 + 10n-5m-23?

Given - M + 2n = 5, then 3 (m-2n) ^ 2 + 10n-5m-23?


∵-m+2n=5
∴m-2n=-5
3(m-2n)²+10n-5m-23
=3(m-2n)²-5(m-2n)-23
=3×(-5)²-5×(-5)-23
=75+25-23
=77



Simplification of sin {[(4N-1) / 4] π - a} · cos {(4N + 1) / 4} π - a}


Integral sum difference formula
sin{[(4n-1)/4]π-a}·cos{{(4n+1)/4}π-a}
={sin([(4n-1)/4]π-a+[(4n+1)/4]π-a)+sin([(4n-1)/4]π-a-[(4n+1)/4]π+a)}/2
=(-sin2a-1)/2
=-1/2-sinacosa



N is an integer, the result of simplifying sin (n π + a) / cos (n π + a)


sin(nπ+a)/cos(nπ+a)=tan(nπ+a)=tana