Given that a and B are opposite numbers, B ≠ 0, m and N are reciprocal, and the absolute value of S is 3, the value of a / b (B of a) + Mn + s is obtained How to do this problem pinch? Who can tell me class?. 555. Urgent... Please!

Given that a and B are opposite numbers, B ≠ 0, m and N are reciprocal, and the absolute value of S is 3, the value of a / b (B of a) + Mn + s is obtained How to do this problem pinch? Who can tell me class?. 555. Urgent... Please!

Given that a and B are opposite numbers, and B ≠ 0, m and N are reciprocal, and the absolute value of S is 3, find the value of a / b (B of a) + Mn + s. A and B are opposite numbers, that is, a + B = 0 = = = > a = - B = = > A / b = - 1MN are reciprocal, that is, Mn = 1 | s | = 3 = = = = = = = > s = + / - 31. When s = 3, the original formula = - 1 + 1 + 3 = 32. When s = - 3, the original formula = - 1 + 1-3 = -

Given that a and B are opposite numbers, m and N are reciprocal, the absolute value of S is 3, find the value of a + B + Mn + s

That is, a + B = 0
mn=1
s=±3
So the original formula = 0 + 1 + (± 3)
=1-3 = - 2 or = 1 + 3 = 4

It is known that AB is opposite to each other, Mn is reciprocal to each other, and M is not equal to N. find the value of - 2Mn + (B + C) divided by (m-n)

Because AB is opposite to each other and Mn is reciprocal to each other
So a + B = 0, Mn = 1
So - 2Mn + (B + a) divided by (m-n)
=-2*1+0/(m-n)
=-2+0
=-2