The least common multiple of 17,14,13,11 Come on!!!!!!!!!!!!!!!

The least common multiple of 17,14,13,11 Come on!!!!!!!!!!!!!!!

34034, they are prime numbers, so they multiply directly

5 out of 9 times 8 out of 19 times 7 out of 30 mixed operation is a fast and urgent process

5 / 9 × 19 / 8 × 30 / 7
=40 of 171 × 7 of 30
=28 / 513

How to calculate 99 times 37 plus 27

I'm glad to be able to answer your question here
99*37+27
=99*37+37-10
=(99+1)*37-10
=3700-10
=3690

1:2004 plus 2:2004. How much does it equal to 2003:2004

1/2004+2/2004+3/2004+…… +2003/2004
=（1/2004）（1+2+3+…… 2003）
=（1/2004）*（2004*1001+1002）
=2004*1001*（1/2004）+（1/2004）*（1002）
=1001+0.5
=1001.5
Method: after 1 / 2004, there is the arithmetic sequence, the sum of the first and the last is 2004, the sum of the second and the penultimate is 2004, and so on, there are 1001 pairs in total, and the last 1002 is left, which is added to the product of 1001 pairs of 2004, and then multiplied by 1 / 2004

What's the equivalent of "1:2004 + 3:2004 + 5:2004 + 7:2004 + 2003:2004"?

The denominator is the same and the numerator is added
Equal to 1 / 2004 + 2 + 3 +. 2003
The molecule can be regarded as (1 + 2003) + (2 + 2002) + (3 + 2001)
There are 1002 2004, so it's equal to 1002

(1 / 6-1 / 3 + 1 / 4) * 24 simple calculation

(1/6-1/3+1/4)*24
=1/6*24-1/3*24+1/4*24
=4-8+6
=10-8
=2

(1 / 2-7 / 5x24 / 7) × 2 / 3

(1 / 2-7 / 5x24 / 7) / / 2 / 3
=(1 / 2-5 / 24) x 2 / 3
=1 / 2 x 2 / 3-5 / 24 x 2 / 3
=3 / 4-5 / 16
=12 / 16-5 / 16
=7 out of 16

(2 / 3-1 / 2 + 1 / 6) △ 24 If you can do it simply, don't do it if you can't, thank you

(2 / 3-1 / 2 + 1 / 6) △ 24
=（4/6-3/6+1/6)/24
=1/3*1/24
=1/72

Simple calculation; 24 × [1 / 2 + 1 / 3-1 / 4-1 / 6] [important process]

24 × [1 / 2 + 1 / 3-1 / 4-1 / 6]
=24*1/2+24/1/3-24*1/4-24*1/6
=12+6-6-4
=8

First simplify the square root of 2 / 3 - (1 / 6 times the square root of 24 - 3 / 2 times the square root of 12), and then find its approximate value
Accurate to 0.01
Square root of (1-8 and 8 / 289)--------
Root 7-2 / 3--------
Given that a satisfies the square root of (2009-A) & sup2; + the square root of a-2010 = a, then a - (the square of 2009)=---------

3 times the square of 3 is about 5.20
The square root of (1-8 and 8 / 289) --- where can I find the square root if 1-8 and 8 / 289 are negative
Radical 7-2 / 3 -------- 11 / 7
The last question is 2010