There are six beads on the counter, which can show several three digits

100、101、102、103、104、105110、111、112、113、114120、121、122、123130、131、132140、141150200、201、202、203、204210、211、212、213220、221、222230、231240300、301、302、303310、311、312320、321330...

Use three beads to represent five digits on a calculator, the maximum can represent (), the minimum can represent ()

On the abacus, the maximum can be 70000, and the minimum can be 30000

There are four beads on the counter, which can show () three digits

A hundred and ten
4 0 0
3 1 0
3 0 1
2 2 0
2 1 1
2 0 2
1 3 0
1 2 1
1 1 2
1 0 3
A total of 10 three digit numbers

The 11 letters probability are written on the 11 cards respectively. Take any 7 of them and find out the probability that the result of arrangement is ability

1 / 11 is the probability of getting a for the first time
1 / 10 is the probability of drawing B for the second time
.
So it's 1 / 11 * 1 / 10 * 1 / 5=

Write the 11 letters of probability on the 11 cards, and select 7 of them. The result is abilit

The probability of a is 1 / 11, the probability of B is 2 / 10, the probability of I is 2 / 9 (the first I) the probability of L is 1 / 8, the probability of I is 1 / 7 (the second I) the probability of T is 1 / 6, the probability of Y is 1 / 5, the probability of ablity is (1 / 11) * (2 / 10) * (2 / 9) * (1 / 8) * (1 / 7) * (1 / 6) * (1

The letters e, e and B are written on the three cards respectively, and the probability that the three cards are randomly arranged in one line and just form the English word bee is ()
A. 23B. 14C. 15D. 13

From the meaning of the question, we can know that this question is a classical probability type. All the events in the experiment can be listed. Three cards are randomly arranged in a row. There are three cases: bee, EBE and EEB, and only one meets the condition. The probability is: 13

What's the probability that seven letters, such as C, C, e, e, I, N and s, will be randomly arranged in one line?
Similarly, write the 11 letters P R o b a b i t y on the 11 cards respectively, and take 7 consecutive cards from them, and find out the probability that the permutation result is a b i t y

Step by step, the first one in the first book is that the s probability is 1 / 7
In the second part, in the case of the first drawing s, the second chapter is that the probability of C is 2 / 6
In the third part, under the first is the second C, the probability of I is 1 / 5
2 / 4 1 / 3 1 / 2 1 / 1 is the probability

C, C, e, e, I, N, s and other seven letters are randomly arranged in a line, then the probability of just being arranged into the English word science is

1*2*1*2*1*1*1/A(7,7)=4/(7*6*5*4*3*2*1)=1/1260

What are the main words to be tested according to the initials in the senior high school entrance examination
What are the main words to be tested according to the initials in the senior high school entrance examination (words with high probability, such as words beginning with a and 26 English letters beginning with B, give me a few examples, white 3Q

I'll give you some examples. Not all of them, but I've done them. Instead, we often test the common prepositions such as "cancer / cancer knowledge improve by mistake, long to, dependent on, believe in, because of". For example, the simple prepositions such as "its" may also be

There are five cards in red, yellow and blue, and the five cards in the same color are all marked with ABCDE five letters. Now take any four of these 15 cards, and the letters should be mutual
There are five red, yellow and blue cards, and the five cards of the same color are marked with ABCDE five letters. Now take any four of these 15 cards, how many kinds of methods are required to have different letters and complete three colors?
Urgent answer and detailed steps! Thank you!

According to the color, there are five choices: A, B, C, D and E
Take the yellow one and remove the red one. There are four choices
Then it's blue, and there are three options, except for the letters that have been selected in the last two times
In the fourth time, there were six, so there were 360 choices

There are six beads on the counter, which can show several three digits