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Y = 2A + bsinx max 3 min 1 find a?
When y is the largest, SiNx = 1, so the original formula can be changed to y = 2A + B = 3
When y is the smallest, SiNx = - 1, so the original formula can be changed to y = 2a-b = 1
The solution is a = 1, B = 1
Let a > 0, b > 0, a + B + AB = 24, then ()
A. A + B has maximum value 8b. A + B has minimum value 8C. AB has maximum value 8D. AB has minimum value 8
∵ a + B + AB = 24 {B = 24 − a1 + a} a + B = 24 − a1 + A + a = 24 + A21 + a = (1 + a) + 251 + a − 2 ≥ 8; ab = 24 − a1 + a · a = 26 − [(1 + a) + 251 + a] ≤ 16, so the answer is B
a> 0, b > 0, 2A + B = 1, then AB is the maximum
Because 2A + B = 1
And 2A + B ≥ 2 √ (2Ab)
So 1 ≥ 2 √ (2Ab)
So √ (2Ab) ≤ 1 / 2
So ab ≤ 1 / 8
So the maximum value of AB is 1 / 8
If and only if a = 1 / 4, B = 1 / 2, the maximum value is obtained
a. B is a positive number, ab = 4, find the minimum of 2A + 3B
2A + 3B > = 2 (2a * 3b) = 2 6ab = 2 24 = 4 6
How to express the arithmetic square root of 3 on the number axis
Can you make the point corresponding to root 2? Let's talk about how to make root 2 first
Draw the coordinates, take a (1,1), take the origin o as the center of the circle, take OA as the radius, draw the arc, and the point intersected on the X axis is the corresponding point of root 2. This is accurate. Understand (Pythagorean theorem of right triangle)
Now take B (√ 2,1), take the origin o as the same center, take ob as the radius, draw an arc, and the point intersecting on the X axis is the point corresponding to √ 3
You only need to calculate the square root, so when you make an arc, you just intersect with the positive half axis of X axis
Don't erase the y-axis at last
If the numbers represented by any two points a and B on the number axis are a and B, please use an equation to express the distance between these two points
The distance between these two points | A-B | (the absolute value of a-b)
If the distance between two points P and Q representing X and - 2 on the number axis is 3, what is x = then?
X = - 5 or 1
The number axis is two points representing X and 2, and the distance between P and Q is 3?
|x-2|=3
x-2=(+/-)3
X = 5 or - 1
How to find the distance between two points on the number axis?
Er... I know how much it is, but I can't express it with arithmetic. Give me a formula
Subtract the coordinates of two points, and then take the absolute value of the difference
Number axis, it seems that it is the first year of junior high school. It is more troublesome to learn coordinates in the future
The numbers represented by two points a and B on the number axis are a and B respectively. If | a | = 3 | B |, and the distance between a and B is 8, find the two numbers a and B
A. The distance between B is | A-B | = 8
2-sided square (a-b) ^ 2 = a ^ 2-2ab + B ^ 2 = 64
|If a | = 3 | B | 2 is the square of edges, a ^ 2 = 9b ^ 2 is obtained
We can get 10B ^ 2-2 * 3 | B | * b = 64
When b > = 0 10B ^ 2-2 * 3 | * b = 4B ^ 2 = 64 B = 4 a = 12
When B
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