(2 / 2) + 2 to the negative m power = 5 / 2, find the value of a; 3. If f (3a-1) > 1, find the value range of real number a

(2 / 2) + 2 to the negative m power = 5 / 2, find the value of a; 3. If f (3a-1) > 1, find the value range of real number a

3. Inequality can be reduced to
loga(3a-1)>loga(a)
1) If a > 1, f (x) increases, 3a-1 > A, a > 1 / 2
So a > 1
2) If 0

2a-3's square-4 > or = 0 to find the value range of a
I don't know why I want to change the number

(2a-3) square-4 > 0 means 2a-3 square > 4 means 2a-3 > 2 or 2a-25 / 2 or a

It is known that the square of (a + 2A + 3) x is greater than the square of (a + 2A + 3) 1-x

The square of a + 2A + 3 = (a + 1) + 2 > 0
Eliminating both sides of inequality at the same time does not change the direction of inequality
That is, x square > (1-x) square
x>1/2

If M ∈ R, then the value range of m in the set {m, square of M + 3M} is

Because it is a set, M is not equal to m ^ 2 + 3M
So the value range of M is that M is not equal to 0 and M is not equal to - 2

1. Which number on the number axis has the same distance to - 26 and 48? 2. Insert three numbers between - 7 and 37 to make the distance between each two of the five numbers equal

﹙－26＋48﹚÷2=11
[37－﹙－7﹚]÷4=11
－7＋11=4,4＋11=15,15＋11=26
The three numbers are 4, 15, 26

Insert three numbers between - 7 and 37 so that the distance between each of the five adjacent numbers is equal, then the sum of the three numbers is______ ．

Let X be the distance between every two adjacent numbers in five numbers. According to the meaning of the question, we get: - 7 + 4x = 37, and the solution is: x = 11, that is, if the three numbers are 4, 15 and 26, then the sum of the three numbers is 4 + 15 + 26 = 45, so the answer is: 45

On the number axis, the number of integers whose distance from the origin is less than 2 is x, the number of positive integers whose distance from the origin is not more than 2 is y, and the number of integers whose distance from the origin is equal to 2 is Z. find the value of X + y + Z

X=3,Y=2,Z=2
X+Y+Z=3+2+2=7

On the number axis, the number of integer points less than 2 from the origin is a, the number of integer points less than 2 is B, and the number of integer points equal to 3 is C. find the value of a + B + C

A = 3 (- 1,0,1)
B = 5 (- 2, - 1,0,1,2)
C = 2 (- 3,3)
So a + B + C = 3 + 5 + 2 = 10

C language programming: input a positive integer n to determine whether it is a prime number

#include <stdio.h>#include <math.h>int main(void){    int nNum;    int i;    int m;  ...

C language: input two positive integers m and n (m ≥ 1, n ≤ 500), output all prime numbers between M and N, output 6 per line
[problem description]
Input two positive integers m and n (m ≥ 1, n ≤ 500), output all prime numbers between M and N, output 6 & per line; prime numbers are positive integers that can only be divided by 1 and itself, and the smallest prime number is 2 &;
[input form]
Enter two positive integers m and N from the keyboard
[input and output example 1] (the underlined part indicates input)
Input m:1
Input n:35
2 3 5 7 11 13
17 19 23 29 31
[example description]
Each line outputs 6 positive integers, and each positive integer is output in% 4D format;
A space should be added after the input prompt. One and only one space should be added after ":"
English letters are case sensitive. Input and output must be strictly in accordance with the sample
#include
int prime(int n);
int main(void)
{
int i,count,m,n;
count=0;
printf("Input m:");
scanf("%d",&m);
printf("Input n:");
scanf("%d",&n);
for(i=m;i

if(flag==1&&n!=1)
There's a mistake here. You're missing=