![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
(2x-27) × 5.7 = 92.34 60-7x = 9x + 40 to solve the equation
(2x-27)×5.7 = 92.34
2x-27 =92.34÷5.7
2x-27=16.2
2x=16.2+27
2x=43.2
x=21.6
60－7x = 9x＋40
7x+9x=60-40
16x=20
x=1.25
Solving equation 8x-34 = 2x + 10
8x-2x=10+34
6x=44
x=3/22
20 = 5-3 / 2x to solve the equation
20=5-3/2x
20+3/2x=5
3/2x=5-20
3/2x=-15
x=-15×2/3
x=-10
RELATED INFORMATIONS
- 1. The equation 2x + 3Y = 30 is transformed into a formula containing x to express y, and x = 3 and y = - 6 are obtained respectively The equation 2x-3y = 0 is expressed by the formula with y which is transformed into ⊙ ﹏ ⊙ B, and y = 1, y = 5 / 3 respectively How many solutions are there for binary power X + y = 5, and how many positive integer solutions are there? Find the positive integer solution of binary linear equation 2x + 3Y = 12
- 2. The equation 2x-3y = 5 is transformed into the expression y of X, then y = ()
- 3. It is known that there are two points B, C, ad = 16cm, BC = 7cm on the line ab. E and F are the midpoint of CD and ab respectively. Find the length of the line EF. Quick, quick
- 4. Given that line AB = 12cm, point C is the third grade branch of AB, and point m is the midpoint of AC, then the length of CM is
- 5. Take any point a on the line L, intercept AB = 16cm, then intercept AC = 40cm, and find the distance between the midpoint D of AB and the midpoint e of AC
- 6. As shown in the figure, C is the midpoint of line AB, point D is on line CB, ad = 4, BD = 2, find the length of line CD
- 7. If line AB = 8cm, C is the midpoint of AB, D is on CB, DB = 1.5cm, then line CD=______ cm．
- 8. It is known that there are two points BC on the line ad, and ab: BC: CD = 2:3:4. If the distance between the midpoint m of AB and the midpoint n of CD is 3cm, the lengths of AB, BC and CD are obtained It is known that there are two points B and C on the line ad, and ab: BC: CD = 2:3:4. If the distance between the midpoint m of AB and the midpoint n of CD is 3cm, the lengths of AB, BC and CD are obtained You have to make a formula,
- 9. Point C is the point on line AB, and point D is the midpoint of BC. If ad = 5cm, then AC + AB is
- 10. As shown in the figure, ad = 3.5cm, BC = 3cm, points D and E are the midpoint of AC and ab respectively, and the length of line EC is calculated
- 11. 2X + 4 × (12-x) = 34,
- 12. (40 - 2x) (28 - 2x) = 364 (solving equation)
- 13. Solving equation (X-2) / (x + 3) = 1 - (2x-13) / (x ^ 2-9) (X+1)/(X-1)+ 4/(X^2-1)=1 1/(2-X)=1/(X-2) - (6-X)/(3X^2-12)
- 14. 2X ^ 2 + 2x-13 = 0 to solve the equation
- 15. Solution equation: 0.1 x-0.4-1 of 1.2 = 0.2 x + 1 of 0.3
- 16. 6.5+3x=15.5 7x-6.5x=24.5 8x-32×5=400 6.5+3x=15.5 7x-6.5x=24.5 8x-32×5=400
- 17. 【2/7X-32】+【2/5X+48】=X Solution x
- 18. 7x of 6 + 1 of 8 = 2 of 9
- 19. 7X+3=2X+18
- 20. The square of (5a + 4b) - (5a-b) (5a + b) =?