It is known that there are two points B, C, ad = 16cm, BC = 7cm on the line ab. E and F are the midpoint of CD and ab respectively. Find the length of the line EF. Quick, quick

If the title is changed to a known line segment ad, there are two points B, C, I think I will do ^ -------- - a f b c e d from the title BF = AB / 2 CE = CD / 2 = > BF + CE = (AB + CD) / 2BF + CE = (ad-bc) / 2BF + CE + BC = (ad-bc) / 2 + BCEF = 9 / 2 + 7ef = 23 / 2

As shown in the figure, it is known that the line segment ad = 10cm, the line segment AC = BD = 6cm. E and F are the midpoint of the line segments AB and CD respectively, and the length of EF is calculated

∵ ad = 10, AC = BD = 6, ∵ AB = ad-bd = 10-6 = 4, ∵ e is the midpoint of the line AB, ∵ EB = 12ab = 12 × 4 = 2, ∵ BC = ac-ab = 6-4 = 2, CD = bd-bc = 6-2 = 4, ∵ f is the midpoint of the line CD, ∵ CF = 12CD = 12 × 4 = 2, ∵ EF = EB + BC + CF = 2 + 2 + 2 = 6cm

As shown in the figure, four points a, B, C and D are on the same straight line, point C is the midpoint of line BD, ab = 5cm, CD = 10cm, find the length of AC and AD

No graph? Suppose the distribution is as follows:
——A——B————C————D——
Well, according to the known
AB=5cm,
BC=CD=10cm
So,
AC=AB+BC=15cm
AD=AB+BC+CD=25cm

Given that the line segment AB = 1.8cm, the point C is on the extension line of AB, and AC = 53bc, then the line segment BC is equal to ()
A. 2.5cmB. 2.7cmC. 3cmD. 3.5cm

As shown in the figure, AC = AB + BC = 53bc, i.e. 1.8 + BC = 53bc, the solution is BC = 2.7 (CM)

As shown in the figure, extend line AB to C so that BC = 4. If AB = 8, then the length of line AC is BC______ Times

If ∵ BC = 4, ab = 8, then AC = 12, the length of ∵ segment AC is three times that of BC

Given the line AB = 3.6, point C is on the extension of AB, AC = 3 / 5BC, find the length of BC

The order of the three points should be C, a and B. (it can't be a, B and C. if possible, AC is bigger than BC, and AC is bigger than 3 / 5BC. It can't be equal, so there's no solution. It can't be ABC.)
AC=3/5BC
BC-AB=3/5BC
BC-3.6=3/5BC
2/5BC=3.6
BC=9

As shown in Figure 7, we know that ab = 18cm, C is a point on AB, and AC: CB = 2:1, D is the midpoint of AC, e is the midpoint of BC
Finding the length of AB and BC
Finding the length of line AE
Use ∵

Let BC be a, then AC be 2A;
AC + BC = 18, namely 3A = 18; a = 6;
So AB = 18; BC = 6
Because e is the midpoint of BC, CE = 3, AC = 2A = 12;
AE=AC+CE=12+3=15.

The length of segment AC is 12 cm when the midpoint m of segment AB and point C divide segment MB into MC: cb-1:2
A.2cm B.8cm C.6cm C.4cm

If the midpoint of the 12cm segment AB is m, and point C divides the segment MB into MC: CB = 1:2, then the length of the segment AC is______ ．

The midpoint of ∵ line AB is m, ∵ am = BM = 6cm, let MC = x, then CB = 2x, ∵ x + 2x = 6, the solution is x = 2, that is, MC = 2cm. ∵ AC = am + MC = 6 + 2 = 8cm

The first question: given the line AB = 12cm, M is the midpoint of AB, C is the point on the straight line AB, and cm: CB = 1:2, find the length of AC. another question, see below. Give it to me as soon as possible
Problem 2: it is known that two points B and C divide the line ad into three parts 2:3:4, e is the midpoint of AD, and CD = 24. Find the length of CE
Don't just give the number

It is known that there are two points B, C, ad = 16cm, BC = 7cm on the line ab. E and F are the midpoint of CD and ab respectively. Find the length of the line EF. Quick, quick