Given that line AB = 12cm, point C is the third grade branch of AB, and point m is the midpoint of AC, then the length of CM is

Given that line AB = 12cm, point C is the third grade branch of AB, and point m is the midpoint of AC, then the length of CM is

There are two cases
①
AC = two thirds AB = 8cm
Cm = half AC = 4cm
②
AC = one third AB = 4cm
Cm = half, AC = 2cm
 

Line AB = 12 cm, point m is the midpoint of AB, point C is on MB and MC: CB = 1:2,

Because AB = 12cm, M is the midpoint of AB, so am = MB = 6cm, and because C is on MB and MC: CB = 1:2, MC = 2cm, CB = 4cm, AC = am + MC = 6 + 2 = 8cm

As shown in the figure, C is the midpoint of line AB, n is the midpoint of line CB, CN = 1cm

Because n is the midpoint of line segment CB, CN = 1cm, so BC = CN + Nb = 2cm, and because C is the midpoint of line segment AB, so AC = BC = 2cm, ab = 2Ac = 4cm, so an = AC + CN = 3cm. The sum of the lengths of all line segments in the figure is: AC + an + AB + CN + CB + Nb = 2 + 3 + 4 + 1 + 2 + 1 = 13cm

Given that C is a point on the line AB, AC equals 5cm, CB equals 3cm, M is the midpoint of AB, what is the length of MC?

MC is 1cm, AB is AC + CB = 8cm, M is the midpoint, MB is 4cm, MC = mb-cb = 4-3 = 1cm

If AB = 4cm, BC = 1cm, then AC = ()
A. 1cmB. 2cmC. 3cmD. 4cm

AC = ab-bc = 4-1 = 3cm, so C

If AB = 4cm, BC = 1cm, then AC = ()
A. 1cmB. 2cmC. 3cmD. 4cm

AC = ab-bc = 4-1 = 3cm, so C

A. If AB = 1cm, BC = 4cm, then AC = --- cm

5 or 3

If AB = 6cm, ac-10cm are intercepted on the straight line m, then the distance between the midpoint of AB and the midpoint of AC is?

Is the title wrong? What does ac-10cm mean? Is AC = 10cm?
If so, it's very simple to see that the number axis coordinates are a = 0cm, B = 6cm and C = 10cm
The coordinates of the midpoint of AB = (6-0) / 2 = 3cm
The coordinates of the midpoint of AC = (10-0) / 2 = 5cm
The distance between the second two midpoint is the difference between them, 5-3 = 2cm

Take any point a on the straight line a, intercept AB = 16 & nbsp; cm, and then intercept AC = 40 & nbsp; cm to find the distance between the midpoint D of AB and the midpoint e of AC

(1) As shown in the right figure, ∵ AB = 16 & nbsp; cm, AC = 40 & nbsp; cm, points D and E are the midpoint of AB and AC respectively ∵ ad = 12ab = 8cm, AE = 12ac = 20cm ∵ de = ae-ad = 20-8 = 12cm; (2) as shown in the above figure, ∵ AB = 16 & nbsp; cm, AC = 40 & nbsp; So the distance between the midpoint D of AB and the midpoint e of AC is 12cm or 28cm

Take any point a on the straight line a, intercept AB = 16 & nbsp; cm, and then intercept AC = 40 & nbsp; cm to find the distance between the midpoint D of AB and the midpoint e of AC

(1) As shown in the figure on the right, ∵ AB = 16 & nbsp; cm, AC = 40 & nbsp; cm, points D and E are the midpoint of AB and AC respectively, ad = 12ab = 8cm, AE = 12ac = 20cm, de = ae-ad = 20-8 = 12cm; (2) as shown in the figure above, ∵ AB = 16 & nbsp; cm, AC = 40 & nbsp; cm, points D and E are the midpoint of AB and AC respectively, ad = 12ab