It is known that there are two points BC on the line ad, and ab: BC: CD = 2:3:4. If the distance between the midpoint m of AB and the midpoint n of CD is 3cm, the lengths of AB, BC and CD are obtained It is known that there are two points B and C on the line ad, and ab: BC: CD = 2:3:4. If the distance between the midpoint m of AB and the midpoint n of CD is 3cm, the lengths of AB, BC and CD are obtained You have to make a formula,

It is known that there are two points BC on the line ad, and ab: BC: CD = 2:3:4. If the distance between the midpoint m of AB and the midpoint n of CD is 3cm, the lengths of AB, BC and CD are obtained It is known that there are two points B and C on the line ad, and ab: BC: CD = 2:3:4. If the distance between the midpoint m of AB and the midpoint n of CD is 3cm, the lengths of AB, BC and CD are obtained You have to make a formula,

Let AB = 2x, then
BC=3X,CD=4X
Mn = 1 / 2Ab + BC + 1 / 2CD = x + 3x + 2x = 6x = 3, x = 0.5
So AB = 2x = 1cm,
BC=3X=1.5cm,
CD=4X=2cm
Note: because AB: BC = 2:3, it is impossible for point C to be between point a and point B. the order of the four points on the line segment can only be a B C D

Given BC = 1-2ab, ad = 2-3ab, CD = 13cm, what is the length of line AB?

Because BC = 1 / 2Ab, AC = 1 / 2Ab
CD=AD-AC=2/3AB-1/2AB=1/6AB=13
So AB = 13 × 6 = 78

If two points c and D on the same line AB are known as ad = 9 / 5bd, AC = 5 / 9CB and CD = 4cm, what is the length of AB

∵AD=9/5BD ==>AC+CD=9/5BD
==>AC+4=9/5BD (CD=4cm)
==>9/5BD-AC=4.(1)
AC=5/9CB ==>AC=5/9(CD+BD)
==>AC=5/9CD+5/9BD
==>AC=20/9+5/9BD (CD=4cm)
==>AC-5/9BD=20/9.(2)
By solving equations (1) and (2), AC = BD = 5
∴AB=AC+CD+BD=5+4+5=14cm.

BC is the two points on the line ad, and CD = 3 / 2 AB, AC = 35 cm, BD = 44 cm. How many cm is the side ad equal to?
Because + is the solution, not the equation

Bd-ac = 0.5ab = 9, so AB = 18, CD = 27; DB + AC - (AB + CD) = 2BC = 34, then BC = 17
So ad = AB + BC + CD = 62

Extend the line AB to C so that BC equals one third of AB, D is the midpoint of AC and BC equals 5cm, then the length of ad is
Have a detailed description

Ad = 1 / 2Ac = 1 / 2 (AB + BC) = 1 / 2 (3bC + BC) = 1 / 2 (3x5 + 5) = 10cm

As shown in the figure, it is known that B and C are two points on the line ad, M is the midpoint of AB, n is the midpoint of CD, Mn = a, BC = B, then the line ad=______ ．

∵ Mn = MB + CN + BC = a, BC = B, ∵ MB + CN = A-B, ∵ m is the midpoint of AB, n is the midpoint of CD, ∵ AB + CD = 2 (MB + CN) = 2 (a-b), ∵ ad = 2 (a-b) + B = 2a-b.so the answer is: 2a-b

Given the line segment AB, extend AB to C to make BC = 12ab, and then extend AB to D reversely to make ad = 23ab. If CD = 26cm, find the length of line segment ab

Let AB = 6x, then BC = 3x, ad = 4x, ∵ AD + AB + BC = DC, ∵ 4x + 6x + 3x = 26, x = 2, ∵ AB = 12

If the line segment AB is known, extend the line segment AB to C so that BC is equal to AB, and intercept ad equal to AC on the reverse extension line of AB, then DB: ab=_____ ,CD：BD=_____ .

Let AB = 1, then DB = 3, CD = 4, BD = 3
DB:AB=3:1 CD:BD=4:3

Point C is the point on line AB, and point D is the midpoint of BC. If ad = 5cm, what is AC + AB?

10
AC+AB=AC+(AC+2CD)=2AD=10

The solution of {3x + 5Y = 3,3x-3y = 11 by addition subtraction elimination method

3x+5y=3.1
3x-3y=11.2
1 minus 2
5y+3y=3-11
8y=-8
Y = - 1 is substituted into 1
3x-5=3
3x=8
x=8/3