The equation 2x-3y = 5 is transformed into the expression y of X, then y = ()

The equation 2x-3y = 5 is transformed into the expression y of X, then y = ()

2X minus 5 divided by 3

Solve the binary linear equation 2x + 3Y = 30 and express y with the formula containing x, and find out the value of Y corresponding to x = 3, x = - 6

From 2x + 3Y = 30
y=(30-2x)/3
Substituting x = 3 into y = (30-2 * 3) / 3 = 8
Substituting x = - 6 into y = (30 + 2 * 6) / 3 = 14

The solutions are as follows: 1. 3x-5y = 6x + 4Y = - 152, 3x-5y = 92x-3y = - 63, 2x-y = 6x + 3Y = - 4

1. 3x-5y = 6 - (1), x + 4Y = - 15 - (2) (1) - (2) * 3, get - 17Y = 51, y = - 3. Substituting (2) get, X-12 = - 15, x = - 3.2, 3x-5y = 9 - (1), 2x-3y = - 6 - (2) (1) * 2 - (2) * 3, get - y = 36, y = - 36; substituting (2) get, 2x + 108 = - 6, x = - 57.3, 2x-y =

3x = 5Y 2x-3y = 1 addition subtraction elimination method

3x=5y.(1)
2x-3y=1.(2)
(1) * 2 - (2) * 3
9y=10y-3
Y = 3 is substituted into (1) to get
x=5
So x = 5, y = 3