Given that the x power of 2 is equal to 3, the x power of 3 is equal to 7, find the x power of 12

Given that the x power of 2 is equal to 3, the x power of 3 is equal to 7, find the x power of 12

12 = 2 × 2 × 3, so the x power of 12 = (x power of 2) × (x power of 2) × (x power of 3) = 3 × 3 × 7 = 63

If the product of (x + 3) (2x-m) does not contain a linear term, then the constant M=_____ The results are as follows_____
2. Calculation: (2x ^ 2-1) (x-4) - (x ^ 2 + 3) (2x-5)
3. If x ^ 3-6x ^ 2 + 11x-6 = (x-1) (x ^ 2 + MX + n), find the value of M, n
4. Solve the equation: 2x (x-3) - (x + 6) (x-3) = x ^ 2 + 12
5. It is known that a, B, C and D are four consecutive odd numbers. Let the smallest odd number be d = 2N-1 (n is a positive integer). When AC BD = 88, the four odd numbers can be obtained
6. Known to expand (x ^ 2-x + 1) ^ 6 to get a12x ^ 12 + a11x ^ 11 + +A2x ^ 2 + a1x + A0, find the value of A12 + A10 + A8 + A6 + A4 + A2 + A0 (the number after a refers to the number a, originally those numbers are very small in the exercise book, with the same size as the power)
You can do as much as you can,

1 m=6 2x^2-18
2 -3x^2-7x+19
3 m=-5 n=6
4 x=2/3
5 19 21 23 25

(-7{n}b{n}){2}*(-ab){3}-[5a{2n}*(-a){3}*b{2n}*b{3}]

{2}(-7{n}b{n})*{3}(-ab)-[5a{2n}*{3}(-a)*b{2n}*{3}b]
=4(-7{{n}}b)*(-9ab)-[10an*(-9a)*4b{n}*9b]
=252a{b}{{n}}-(-3240{a}{b}{n})
=252a{b}{{n}}+3240{a}{b}{n}