1+2+3+...+2006+2007+2008+2007+2006+...+3+2+1

1+2+3+...+2006+2007+2008+2007+2006+...+3+2+1

=(1+2007)x2007+2008=4032064

2008-1+2-3+4-.+2006-2007
With simple calculation, know the speed of the answer, thank you!

2008-1+2-3+4-.+2006-2007
=-1+2-3+4-.+2006-2007+2008
=(-1+2)+(-3+4-).+2006+(-2007+2008)
=1+1+...1
=1004
There are 1004 groups in total

(-4)^2007 ×(0.25)^2006

(-4)^2007 ×(0.25)^2006
=(-4)^2007 ×(1/4)^2006
=-(4^2007/4^2006)
=-4

How to solve the problem of 0.25 ^ 2007 x 4 ^ 2006?
It is suggested that n ^ m means m power of n

0.25^2007 X 4^2006
=0.25×0.25^2006 X 4^2006
=0.25×（0.25×4）^2006
=0.25×1
=0.25

Calculate 0.25 ＾ 2006 × 4 ＾ 2007 to process Oh!

0.25＾2006×4＾2007
=0.25＾2006×4＾2006×4
=(0.25×4)^2006×4
=1^2006×4
=4

(- 2) ^ 2 + 100 ÷ (- 2) ^ 3 ＋ (- 5) ^ 2 ＋ (0.25) ^ (2007) × 4 ^ (2006)

(-2)^2+100÷(-2)^3÷(-5)^2+(0.25)^2007×4^2006
=4+100÷(-8)÷25+(0.25x4）^2006X0.25
=4-1/2+0.25
=4-1/4
=15/4
Can it solve your problem?

1-1 / 2-1 / 4 -. 1 / 256 =? Simple calculation method

1-1/2-1/4-.1/256=1-（1/2+1/4-.+1/256+1/256）+1/256=1/256

1 △ 4 × 2 × 20 × 185 is calculated by a simple method

1÷4×2×20×185
=2×20÷4×185
=40÷4×185
=10×185
=1850

Given AB = 1, try to find the value of the fraction AA + 1 + BB + 1

The original formula is a (B + 1) (a + 1) (B + 1) + B (a + 1) (a + 1) (B + 1) = 2Ab + A + bab + A + B + 1 = 2 + A + B2 + A + B = 1

High school mathematics f (x) = 1 / X-1, find f (X & # 178;)
Seeking speed

f（x²）=1/x^2-1