Given that logm (5) > logn (5) (M > 0, n > 0, n is not equal to 1), try to compare the size relationship of M.N

Given that logm (5) > logn (5) (M > 0, n > 0, n is not equal to 1), try to compare the size relationship of M.N

logm5=log2（5）/log2（m）
logn5=log2（5）/log2（n）
log2（5）/log2（m）>log2（5）/log2（n）
So: log2 (m)

Let m > 0 and m not equal to 1. If logm81 = 2, then logm3=

logm81=2 => m^2=81
Because m > 0 and M is not equal to 1
So m = 9
So logm3 = 1 / 2

Compare the size of loga (x + 2) and loga (2x + 5) (a is greater than 0, a is not equal to 1)

loga(x+2)-log(2x+5)
=loga[(x+2)/(2x+5)]
When A1 so log a (x + 2) > log a (2x + 5)
When a > 1, loga [(x + 2) / (2x + 5)]

Let a be greater than 0 and a ≠ 1, M = loga (a ^ 2 + 1), n = loga (A-1), P = loga (2a), and compare the MNP sizes
Why is a ^ 2 + 1 > 2A?

Is your logarithm based on a?
If yes, it can be seen from n = loga (A-1) that a > 1
And (a ^ 2 + 1) > (A-1)
2a>a-1
a^2+1>2a
There are m > P > n

If a is greater than 0 and a is not equal to 1m, then it is the third power of loga + 1 and N is the square of loga plus 1

If a > 1, M > n
a < 1,m < n

Given a + B = 3, ab = 1, then the value of AB + Ba is equal to______ ．

AB + Ba = A2 + b2ab = (a + b) 2 − 2abab, ∵ a + B = 3, ab = 1, ∵ a + b) 2 − 2abab = 9-2 = 7, so the answer is 7

If a + B = 1 / A + 1 / B, and a + B is not equal to 0, then ab=

a+b=1/a+1/b,
a+b=(a+b)/ab
1=1/ab
ab=1

Given that AB is opposite to each other, CD is reciprocal to each other, and a is not equal to zero, find the value of a + B / 100A + (A / b) ^ 2013 - (CXD) ^ 2012

That is, B = - A
So a + B = 0
a/b=-1
And CD = 1
So the original formula = 0 / (100a) + (- 1) ^ 2013-1 ^ 2012
=0+(-1)-1
=-2

If a and B are reciprocal, then AB is equal to?

Because a and B are reciprocal
So AB = 1
AB/2009=1/2009
The answer is one in two thousand nine

a. B is negative reciprocal of each other. What is ab equal to?
1 or - 1! One says 1, one says - 1.

If the product of two numbers is equal to 1, then the two numbers are reciprocal
It is known that AB is negative reciprocal to each other ∧ AB = - 1