High school mathematics ^ f / 2 = X-1

High school mathematics ^ f / 2 = X-1

If t = 1 / x, then x = 1 / T
f(t)=（1/t)/(1-1/t^2)
=t/(t^2-1)
f(x)=x/(x^2-1)

Finding f (x) when f (x) + F (1 / x) = 1 + X

F(x)+f(1/x)=1+X
F(1/X)+F(X)=1+1/X
F(1)+F(1)=1+1=2 ==>F(1)=1
F(-1)+F(-1)=0 ==>F(-1)=0

What does f (X-2) = f (- X-2) mean in high school mathematics

1. Let (X-2) + (- X-2) / 2 = - 2, then x = - 2 is the axis of symmetry of the function. Compare a and B. 2. Find the period. F (x) even function: F (X-2) = f (x + 2), then f (x) = f (x + 4), so the period T = 4f (x) odd function: F (X-2) = - f (...)

The relationship between F (x) and f (1 / x) in
Let f (x) = f (1 / x) ㏒ x + 1, then f (10) is?

f(x)=f(1/x)lgx+1 )
Replace x with 1 / X
f(1/x)=-f(x)lgx+1
Substituting x = 10 into the above two formulas:
f(10)-f(1/10)=1
f(10)+f(1/10)=1
So f (10) = 1

High school mathematics problem f (x-1 / x) = (x + 1 / x) (x + 1 / x) for f (x + 1) solution
I won't, thank you

∵ f (x-1 / x) = (x + 1 / x) (x + 1 / x) = = > F (x-1 / x) = x & sup2; + 1 / X & sup2; + 2 = = > F (x-1 / x) = x & sup2; + 1 / X & sup2; - 2 + 4 = = > F (x-1 / x) = (x-1 / x) & sup2; + 4 ∵ f (x) = x & sup2; + 4, so f (x + 1) = (x + 1) & sup2; + 4 = x & sup2; + 2x + 5

High school mathematics question bank: Let f (x) = 4 ^ X / 4 ^ x + 2, sum s = f (1 / 2002) + F (2 / 2002) + +f(2001/2002)

F (T) + F (1-T) is reduced to 1, so let s add in reverse order, and prime minister's end is equal to 1, so 2S = 2001, s = 2002 / 2

F (x) = 1 / 2 x ^ 2 - 3x + LNX

For f (x), f '(x) = x-3 + 1 / x, Let f' (x) = 0, (the domain of definition of F (x) is known to be x > 0), the solution is X1 = (3-radical 5) / 2 or x2 = (3 + radical 5) / 2
When x belongs to (0, x1) and (X2, positive infinity), f '(x) > 0; when x belongs to (x1, x2), f' (x)

What is f (x) 'in senior high school mathematics questions

It should be f '(x), which represents the derivative of the original function f (x)
If the function f (x) is differentiable at every point in (a, b), then f (x) is said to be differentiable on (a, b), then the derivative function of F (x) can be established

How do complex fractions change into fractions?

________
（1+x^2)
Then add it up to get:
（2+x^2)
________
（1+x^2)
In the same way, we can get the following result:
-x^2
________
（1+x^2)
PS: to change the sign without brackets!
Multiply by the reciprocal to get:
Denominator and numerator offset
x^2+2
- _______
x^2
PS: the front is the symbol!

Is the complex fraction a fraction?
I think so, but there is a problem. The definition of fraction is a / b. both a and B are integers, but the denominator of complex fraction is also a fraction. Is it redefining complex fraction!

Just according to the definition of fraction, such as a / B, a and B are integers. If B contains unknowns and B is not equal to 0, it is called fraction
Complex fraction generally refers to the formula containing fraction in numerator or denominator