A divided by B = 6a and the least common multiple of B () (AB is not equal to 0)

A divided by B = 6a and the least common multiple of B () (AB is not equal to 0)


Analysis:
Because a divided by B = 6
That is, a = 6B
So the least common multiple of a and B (a)
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If the function F X is equal to (a + b) x + AB (a is greater than 0, B is greater than 0,) and f (- 1) = 8, then the minimum value of F (0)


F (x) = (a + b) x + AB, f (- 1) = 8, that is - (a + b) + AB = 8, so a + B = AB-8 ∵ a > 0, b > 0 ∵ a + B ≥ 2 √ (AB), that is AB-8 ≥ 2 √ (AB) ab-2 √ (AB) - 8 ≥ 0 [√ (AB) - 4] [√ (AB) + 2] ≥ 0 ∵ √ (AB) + 2 > 0 ∵ √ (AB) - 4 ≥ 0, that is √ (AB) ≥ 4 ∵ ab ≥ 16, that is, the minimum value of F (0) = AB is 16



What is ab > 0. (a + b) (1 / A + 1 / b) greater than or equal to?


ab>0.
(a-b)²>=0
a²+b²>=2ab
(a+b)(1/a+1/b)
=(a+b)(a+b)/ab
=(a²+b²+2ab)/ab>=4ab/ab=4
So, AB > 0. There are: (a + b) (1 / A + 1 / b) > = 4



As shown in the figure, in the parallelogram, bisectors BM and DN of ∠ ABC and ∠ ADC intersect AC at points m and n
Prove that quadrilateral bmdn is parallelogram


Certification:
Connect BD, ∠ AC to point o
A quadrilateral ABCD is a parallelogram
∴AB=CD,∠ABC=∠ADC,∠BAM=∠DCN,BO=DO,AO=CO
Am and BN are bisectors
∴∠ABM=∠CDN
∴△ABM≌△CDN
∴AM=CN
∴MO=NO
The quadrilateral bmdn is a parallelogram



The degree of a base angle of an isosceles triangle is 12 times of the vertex angle. What is the vertex angle of this triangle?


Let the degree of the base angle of this triangle be x, then x + X + 2x = 180 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 4x = 180 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 4545 × 2 = 90 A: the top angle of this triangle is 90 degrees



For an isosceles triangle, the ratio of the top angle to the bottom angle is 4:1. What is the top angle of the triangle


Let the base angle be x degree
According to the internal angle of triangle and 180 degrees, the equation is established
4x+x+x=180
6x=180
x=30
So the bottom angle is 30 ° and the top angle is 120 °



The degree ratio of a vertex angle to a base angle of an isosceles triangle is 4:1. What is the base angle of the triangle? Is the result of 180 / (4 + 1) = 36 ° 36x4 = 144 ° right?


I don't think it's right. The base angle I made is 30 degrees
Analysis, do not know if you have learned to set unknowns, if you have, you should be able to understand
Let the degree of the base angle be x, then the vertex angle can be expressed as 4x. The sum of the internal angles of a triangle is 180 degrees, which is also an isosceles triangle, so the base angles are equal, that is, x + X + 4x = 180 degrees, and 6x = 180, x = 30



The ratio of the top angle to the bottom angle of an isosceles triangle is 1:4. Its bottom angle is () degrees and its top angle is () degrees


20
eighty



An isosceles triangle, its vertex angle and a base angle degree ratio is 1:4, its vertex angle is (), one of the base angles is ()


Top angle: 20 degree bottom angle: 80 degree



1×2×3×4×...×95×96×97×98×99×100=?


It's 100!