Fill 11, 13, 15, 17, 19 in the cross shaped grid to make the sum of the three numbers in each vertical line and each horizontal line equal. How do you arrange them?

15 in the middle, 11 and 19 in the horizontal, 13 and 17 in the vertical,

Fill in the nine squares of the square with the nine numbers 1-9, so that the sum of the three numbers on the horizontal, vertical and oblique lines is equal to 17
I each number must not be repeated

It can't be 17! It should be 15! Because 17 * 3 = 51 > from 1 to 9
8 1 6
3 5 7
4 9 2

The number 123456789 is filled in the nine palace grid, so that the three numbers on each horizontal, vertical and oblique line add up to 15. How many ways can I fill in?

618
seven hundred and fifty-three
two hundred and ninety-four
This is a way of filling in. In fact, all the others are just changing the number to another position. The unchanged thing is that 5 must be filled in the middle position

3.5.7.9.11.13.15.17.19 fill in the nine palace grid. I use the formula of the nine palace grid, but it's not right,
I've come up with it. I just want to see if your opinions are different from mine

5 19 9
15 11 7
13 3 17
5 15 13
19 11 3
9 7 17
9 19 5
7 11 15
17 3 13
wait.

Nine square game: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 in 16 squares
So that all horizontal, vertical, nine groups of tetragons, the sum of four numbers of two diagonals is equal to 64

31 3 5 25
9 21 19 15
17 13 11 23
7 27 29 1
There should be no problem.

51 / 17 / 19 2 / 3 / 4 / 15 18 / 169 / 3 / 26 99 and 7 / 3 of 8

51/17/19 =51*19/17=57
2/3/4/15 =2/3*15/4=5/2
18/169/3/26 =18/169*26/3=12/13
7 / 3 of 99 and 8 = 99 / 3 + (7 / 8) / 3 = 33 + 7 / 24 = 33 and 7 / 24

It is known that AB is not equal to 0, and the product of the square of a plus AB minus 2 times the square of B equals 0. Then what is the value of (2a-b) / (2a + b)?

AB is not equal to 0, the square of a + ab-2 times the square of B = 0, then 2a-b / 2A + B =?

If X & sup2; + Y & sup2; = 1, x > 0, Y > 0, and loga (1 + x) = m, loga1 / 1-x = n, then loga ^ y is equal to

Log a (1 + x) = m, log a (1 / (1-x)) = Na ^ m = 1 + X, a ^ n = 1 / (1-x) because log a ^ y = log (a, (1-x ^ 2) ^ (1 / 2)) = (1 / 2) log (a, (1-x ^ 2) = (1 / 2) (log (a, (1 + x)) + log (a, (1-x)) = (1 / 2) (m-n), so log a ^ y = (m-n) / 2

Let a > 1, y = | loga ^ x | (a is the base) be defined as [M, n] (m)

You can know this by drawing!
When y = 1, there are two values of X, one is a, the other is 1 / A, so the length of [M, n] is equal to A-1 / a = (a ^ 2-1) / A

Fill 11, 13, 15, 17, 19 in the cross shaped grid to make the sum of the three numbers in each vertical line and each horizontal line equal. How do you arrange them?