Sequence 23,27,26,8,29,1,32, ()

Sequence 23,27,26,8,29,1,32, ()

0
The first, third, fifth and seventh digits are arithmetic sequence
The second, fourth, sixth and eighth bits are cubes of 3, 2, 1 and 0 respectively

The sum of the first four terms of an arithmetic sequence is 26, the sum of the last four terms is 110, and the sum of all terms is 187

a1+a1+d+a+2d+a1+3d=26````(1)
an+an-d+an-2d+an-3d=110```(2)
(1)+(2)=4(a1+an)=136,a1+an=34
(a1+an)*n/2=187,n=11

Given the following sequence: 11, 12, 22, 13, 23, 33, 14, 24, 34, 44 (1) 2329 is the second______ (2) item 244 is______ (3) the sum of the first 30 items is______ ．

(1) 2329 is the 23rd number of group 29. Group n consists of N fractions. From group 1 to group 28, there are 1 + 2 + 3 + + 28 = 28 × 292 = 406 fractions, so 2329 is in item 406 + 23 = 429. (2) because 21 × 20 = 420, 22 × 21 = 462, 23 × 22 = 506, item 244 is in group 22, and the first 21 groups have 21 × 222 = 231 fractions The number of (13 + 2) + (13 + 1) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + (3) + (2) + (2) + (2) + (2) + (2) + (2) + (2) + +17（1+2+… +7) So the answer is: 42913221778