How many hard seat tickets do you need to prepare for a full stop train between Beijing and Shanghai at 15 stations?

How many hard seat tickets do you need to prepare for a full stop train between Beijing and Shanghai at 15 stations?


(14+13+12+11+10+9+8+7+6+5+4+3+2+1)*2=210



Two trains are running on a section of double track. Train a is 180 meters long with a speed of 20 meters per second, while train B is 260 meters long with a speed of 24 meters per second
(2) if two trains are running in opposite directions, find out the time it takes for two trains to meet each other from the front to the rear. There should be process and brief analysis!
(Note: the equation can only be used once a dollar, but it can be set indirectly) I am a poor person, but I still need to have a reward for wealth


Taking car a as the reference frame (i.e. assuming that car a does not move), we have:
(1) If the two vehicles are in the same direction, the relative displacement of vehicle B is 440m and the relative speed is 4m / s, so the time is 110s
(2) If the two cars are reversed, the relative displacement of car B is 440m and the relative speed is 44m / s, so the time is 10s



In a section of double track, two trains run in the same direction, a train speed is 20 meters per second, B train speed is 24 meters per second
On a section of double track, two trains run in the same direction. The speed of train a is 20 meters per second, and that of train B is 24 meters per second. If the total length of train a is 180 meters, the time for train B to catch up with train a to completely exceed train a (i.e. wrong train) is - seconds
I hope someone can do my niece's homework before Sunday afternoon,
Sorry, car B is 160 meters long!


Time = distance / speed
The distance between train B and train a is the sum of the length of two trains, and the speed is the speed difference between two trains,
(160 + 180) / (24-20) = 85 (seconds)
I'm also in grade one. This is what I should do. Don't forget to give me extra points!