On a section of double track, two trains run in the same direction. The speed of train a is 20 meters per second, and that of train B is 24 meters per second The total length of the train is 180 meters, and the time for train B to catch up with train a to completely exceed train a (i.e. wrong train) is calculated Set up equations to do

From the front of train B to catch up with the rear of train a, to the rear of train B and leave train a,
The actual distance should be a train length + B train length
I don't know whether it is the length of one train or two trains?
Let's count it as the length of a train,
Setting: the time of passing is x seconds
180+180=X（24-20）
10. That is, the wrong time is 90 seconds

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1. On a section of double track, two trains run in the same direction. The speed of train a is 20 meters per second, and that of train B is 24 meters per second. If the total length of train a is 180 meters and that of train B is 160 meters, the time taken for train B to completely exceed that of train a (i.e. wrong train) is 30 minutes___
2. In a section of double track railway, two trains pass at the same time, one speed is 20 meters per second, one speed is 24 meters per second, and the length of the train is 180 meters and 160 meters respectively On a section of double track railway, two trains pass by at the same time. The speed of one train is 20 meters per second, the speed of one train is 24 meters per second, and the length of two trains is 180 meters and 160 meters respectively
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